Complete Question
The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of significance,perform a hypothesis test to see if the true mean weight is less than 4 ounce.
Answer:
Yes the true mean weight is less than 4 ounce
Explanation:
From the question we are told that
The random sample is ![n = 15](https://tex.z-dn.net/?f=n%20%3D%2015)
The mean weight is
The standard deviation is ![\sigma = 0.5 \ ounce](https://tex.z-dn.net/?f=%5Csigma%20%3D%200.5%20%5C%20ounce)
The level of significance is ![\alpha = 0.05](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%200.05)
So
The null hypothesis is ![H_o : \mu \ge 4](https://tex.z-dn.net/?f=H_o%20%3A%20%5Cmu%20%5Cge%204)
The alternative hypothesis is ![H_a : \mu < 4](https://tex.z-dn.net/?f=H_a%20%3A%20%5Cmu%20%3C%204)
Generally the critical value which a bench mark to ascertain whether the null hypothesis is true or false is mathematically represented as
![t_{0.05} = 1.79](https://tex.z-dn.net/?f=t_%7B0.05%7D%20%3D%201.79)
This value is obtained from the critical value table
Generally the test statistics is mathematically represented as
![Test \ Statistics (ST) = \frac{\= x - \mu }{\frac{\sigma}{\sqrt{n} } }](https://tex.z-dn.net/?f=Test%20%5C%20Statistics%20%28ST%29%20%20%3D%20%5Cfrac%7B%5C%3D%20x%20-%20%5Cmu%20%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%20%7D)
=> ![ST = \frac{3.8 -4 }{\frac{0.5}{\sqrt{20} } }](https://tex.z-dn.net/?f=ST%20%3D%20%5Cfrac%7B3.8%20-4%20%7D%7B%5Cfrac%7B0.5%7D%7B%5Csqrt%7B20%7D%20%7D%20%7D)
![ST = - 1.79](https://tex.z-dn.net/?f=ST%20%3D%20-%201.79)
So since ST is less than
then the null hypothesis would be rejected and the alternative hypothesis would be accepted so
Thus the true mean weight is less than 4
Transverse waves is the answer.
Hope I helped if you need anything else ask me
<h2>
Answer:</h2>
<em>Hello, </em>
<h3><u>QUESTION)</u></h3>
<em>✔ We have Ek = 1/2m x v² </em>
- Ek = 1/2 x 79.8 x 16²
- Ek = 10 214.4 J
In order to come to a complete stop, the cyclist must convert all his kinetic energy into thermal energy. Given that the braking force opposes movement, the work is therefore resistant, i.e. W = -10 214.4 J.
Answer:
c The amount of water that goes in each pot
Answer: τ = 0
Explanation:
At constant angular velocity there is no angular acceleration therefore no torque.
τ = Iα