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Vladimir79 [104]
3 years ago
13

The interest rate that the Fed charges banks that borrow money from it is called A. the discount rate. B. the federal rate. C. t

he monetary rate. D. the bank-member rate.
Physics
2 answers:
son4ous [18]3 years ago
7 0
The answer is A. the discount rate.
pickupchik [31]3 years ago
4 0

Answer:

The correct answer is A. The interest rate that the Fed charges banks that borrow money from it is called the discount rate.

Explanation:

The discount rate is the interest rate at which a bank can sell (rediscount) bills of exchange to the central bank. This enables it to obtain liquidity in the short term. It pays the discount rate as a price (as a discount from the nominal value).

The Federal Reserve uses two discount rates for very short-term loans it gives to financial institutions during the "discount window": the "primary rate" and the "secondary rate”.

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Read the scenario below and answer the question that follows.
hoa [83]
The answer you are looking for is D most of those are signs of anxiety
8 0
2 years ago
See the attachment included with this note
alexdok [17]

The angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.

<h3>What is the angular velocity of the propeller?</h3>

The angular velocity of the propeller in rad/s is given as follows:

  • 1 rev/m = 2π/60 rad/s.

1300 rev/min = 1300 * 2π/60 = 136.1 rad/s.

b. The linear velocity, v = radius * angular velocity

Linear velocity, v = 2.25/2 * 136.1

v = 153.1 m/s

c. Centripetal acceleration, a = \frac{v^{2}}{r}

a = \frac{(153.1)^{2}}{1.125} = 20835.2\:ms^{2}

Centripetal acceleration in terms of g; g = \frac{20835.2}{9.81} = 2123.8 g

Therefore, the angular velocity of the propeller is 136.1 rad/s; linear velocity is 153.1 m/s; centripetal acceleration 20835.2 m/s² and 2123.8 g.

Learn more about angular velocity and centripetal acceleration at: brainly.com/question/10703948

#SPJ1

7 0
2 years ago
The rotating loop in an AC generator is a square l on each side. It is rotated at frequency f in a uniform field of B. The gener
spin [16.1K]

Answer:

Explanation:

Area of square loop = L²

Flux Φ = area x magnetic field

= L²B

Frequency = f

angular velocity ω = 2πf

a )

Let at time t = 0 , the magnetic field is making 90 degree with the face of the loop

flux through loop = L²B

After time t , coil will turn by angle ω t = 2πft

Flux through the loop = L²B cosω t

Φ (t) = L²B cosω t

= L²B cos2πft

b )

emf induced e

= - d/dt [Φ (t)]

= - d/dt [ L²B cosω t]

= L²B ω sinω t

= L²B 2πf sin2πft

c )

current = e / R

(L²B ω/ R ) sinω t

Power delivered

P(t) = VI ,

VOLT X CURRENT

= AB ω sinω t X ( AB ω/ R ) sinω t

= L⁴B² 4π²f²/R sin²2πft

e )

torque = MB sinω t

τ(t) = i(L²B ) sinω t

= (L²B ω/ R ) sinω t x (L²B ) sinω t

= (L²B  )²ω/ R sin²ω t

= (L²B  )² 2πf/ R sin²2πft

8 0
3 years ago
A stationary boat bobs up and down with a period of 2.4 s when it encounters the waves from a moving boat.
lapo4ka [179]
It seems like the question is asking for the frequency.
Given: 
Time period (T) = 2.4 sec

Frequency (f) =? 

We know that the formula for frequency is:

Frequency (f) = 1/time period (T) 

= 1 / 2.4 s 

= 0.42 Hz. is the frequency for this problem.
8 0
3 years ago
HELP ASAP! <br>why is rolling friction much smaller than sliding friction? Also give an example.​
IceJOKER [234]

Answer:

Rolling friction is much smaller than sliding friction because Rolling friction is considerably less than sliding friction as there is no work done against the body that is rolling by the force of friction. For a body to start rolling a small amount of friction is required at the point where it rests on the other surface, else it would slide instead of roll.

Rolling Friction example: Anything with weels (cars,skateboards) or a ball rooling.

Sliding Friction example: Bicycle brakes,skinning your knee walking,writing.

6 0
3 years ago
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