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BlackZzzverrR [31]
3 years ago
5

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball

's acceleration is 760 m/s2 and the vertical or y component of its acceleration is 770 m/s2. The ball's mass is 0.40 kg. What is the magnitude of the net force acting on the soccer ball at this instant?
Physics
1 answer:
dedylja [7]3 years ago
3 0

Answer:

Magnitude of net force will be 432.758 N  

Explanation:

We have given x component of acceleration a_x=760m/sec^2

And vertical component of acceleration  a_y=770m/sec^2

Mass of the ball m = 0.40 kg

So net acceleration a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2

Now according to second law of motion

Force = mass × acceleration

So F = 0.40×1081.896 = 432.758 N

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To solve this problem we will consider the definition of Minimum Energy, as the change between the minimum voltage and its distance. Mathematically it can be written as

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Question is missing:

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Explanation:

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F=G\frac{m_1m_2}{r^2}

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r is the separation between the objects

In this problem, we have

m_1 = 1.99\cdot 10^{30} kg is the mass of the sun

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Solving the equation, we find

F=(6.67\cdot 10^{-11})\frac{(1.99\cdot 10^{30})(1.90\cdot 10^{27})}{(7.79\cdot 10^{11})^2}=4.16\cdot 10^{23} N

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