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Liula [17]
3 years ago
13

Derek spends three dollars on breakfast and $5.50 on lunch every school day how much does he spend on breakfast and lunch in a s

chool week
Mathematics
2 answers:
maks197457 [2]3 years ago
7 0

(3+5.50)5

8.50*5=42.5

Derek spends $42.50 each school week.

Vikki [24]3 years ago
7 0
3.00+5.50=8.50
8.50
x5
———
42.5
42.5$ a week is spent on breakfast and lunch
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Travis spies an owl in a tall tree. He estimates the height of the tree to be 85 feet and the angle of elevation to the bird fro
anyanavicka [17]

Answer:

63.44 feet

Step-by-step explanation:

tan(68 degrees)= 85/y  

y tan (68 degrees)=85

y=85/tan(68 degrees) ( cross multiply)

y = 34.34 feet

tan (41 degrees)=85/x+y

(x+y)tan(41 degrees)=85

x+y=85/tan 41 degrees

x=85/tan(41 degrees) - y

x= 85/tan (41 degrees)-(34.34) (cross multiply)

Therefore, Travis stepped back 63.44 feet to gain a better view!

7 0
2 years ago
Rewa Delta Union Rugby CEO has become concerned about the slow pace of the rugby games played in the current union rugby, fearin
ozzi

Answer:

We conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

Step-by-step explanation:

We are given that Before the meeting, the mean duration of the 15-sided rugby game time was 3 hours, 5 minutes, that is, 185 minutes.

A random sample of 36 of the 15-sided rugby games after the meeting showed a mean of 179 minutes with a standard deviation of 12 minutes.

Let \mu = <em><u>mean duration of 15-sided union rugby games after the meeting.</u></em>

So, Null Hypothesis, H_0 : \mu \geq 185 minutes      {means that the mean duration of 15-sided union rugby games has increased or remained same after the meeting}

Alternate Hypothesis, H_A : \mu < 185 minutes     {means that the mean duration of 15-sided union rugby games has decreased after the meeting}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean duration of 15-sided union rugby games = 179 min

            s = sample standard deviation = 12 minutes

            n = sample of 15-sided rugby games = 36

So, <u><em>the test statistics</em></u>  =  \frac{179-185}{\frac{12}{\sqrt{36} } }  ~ t_3_5

                                       =  -3

The value of t test statistics is -3.

<u>Now, at 1% significance level the t table gives critical value of -2.437 at 35 degree of freedom for left-tailed test.</u>

Since our test statistic is less than the critical value of t as -3 < -2.437, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean duration of 15-sided union rugby games has decreased after the meeting.

6 0
3 years ago
Find the next term if the sequence: 5, 5, 10, 30, 120, 600
adell [148]

Answer:

3600

Step-by-step explanation:

5 * 5 = 1

5 * 2 = 10

.

.

.

600 * 6 = 3600

5 0
2 years ago
Which of the following possibilities will form a triangle?
s2008m [1.1K]

Answer:

D

Step-by-step explanation:

Triangle Side Theorem: The two smaller sides of a triangle

must be greater than the largest side

8 + 9 > 16

6 0
2 years ago
Spencer, Jaclyn, and Ayden go shrimping in
larisa [96]

The total pounds of shrimp they catch is 9.625 pounds

<h3>Sum of values and decimals</h3>

Decimal number are numbers that has decimal points. Given the following information;

The total shrimp Spencer catch = 2 pounds

The total shrimp Jaclyn catch = 3.25 pounds

The total shrimp Ayden catch = 4.375 pounds

Determine the total pounds of shrimp they catch

Total shrimp = 2 + 3.25 + 4.375

Total shrimp = 9.625 pounds

Hence the total pounds of shrimp they catch is 9.625 pounds

Learn more on sum of decimals here; brainly.com/question/1827193

#SPJ1

7 0
1 year ago
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