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a = (Vf - Vi)/t ; where distance d = [2(t)]/(4+t), t = 5secs, and Vi = 0
a = [(2t)/(4+t)]/t <---- working equation
a = {[2(5)]/9}/5 <---- cancel 5
a = 2/9 ft/s^2 <---- Answer
Explanation:
It is given that,
Diameter of loop, d = 1.4 cm
Radius of loop, r = 0.7 cm = 0.007 m
Magnetic field,
(A) Magnetic field of a current loop is given by :
I is the current in the loop
I = 27.85 A
(B) Magnetic field at a distance r from a wire is given by :
r = 0.00222 m
Hence, this is the required solution.
Answer:
The current would be same in both situation.
Explanation:
Given that,
Current I = 13 A
Number of turns = 23
We need to calculate the induced emf
Using formula of induced emf is
For N = 1
We need to calculate the current
Using formula of current
Put the value of emf
Now, if the number of turn is 22 , then induced emf would be
Then the current would be
Hence, The current would be same in both situation.
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