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poizon [28]
3 years ago
14

Which option BEST describes the position of the Sun, the Moon, and Earth during the new moon phase and the MOST LIKELY effect of

the phase on the petrel?
A.

The Sun, the Moon, and Earth are in a straight line, with Earth between the Sun and the Moon. The petrel will be very active because there will be a lot of light reflected by the Moon.

B.

The Sun, the Moon, and Earth are in a straight line, with the Moon between the Sun and Earth. The petrel will be less active because there will not be any light reflected by the Moon.

C.

The Sun, the Moon, and Earth are in a straight line, with the Moon between the Sun and Earth. The petrel will be very active because there will be a lot of light reflected by the Moon.

D.

The Sun, the Moon, and Earth are in a straight line, with Earth between the Sun and the Moon. The petrel will not be very active because there will not be any light reflected by the Moon..
Physics
1 answer:
artcher [175]3 years ago
3 0
A!!!!!!!!!!!!!!!!aaaaaaaaaaaa
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Anastaziya [24]

Answer:

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8 0
3 years ago
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In billiards, the 0.165 kg cue ball is hit toward the 0.155 kg eight ball, which is stationary. The cue ball travels at 5.8 m/s
Damm [24]

Answer:

another ball velocity = 3.92 m/s and with 30° clockwise from initial direction

Explanation:

given data

mass m1 = 0.165 kg

mass m2 = 0.155 kg

before collision velocity v1 = 5.8 m/s

before collision velocity v2 = 0

angle =  35.0° from initial direction

after collision 1st ball velocity v3 = 3.2 m/s

to find out

after collision another ball velocity v4

solution

we consider here ball move in x axis and after collision 1st ball move upside of x axis with angle 35 degree and other ball move downside with x axis with angle θ

so from conservation of momentum we say

m1v1 = m1v3cos35 + m2v4cosθ   with x axis    .............1

m1v3sin35 = m2v4sinθ                   with y axis  .............2

so from 1 equation

0.165 × 5.8 = 0.165(3.2)cos35 + 0.155(v4)cosθ

v4 cosθ  = 3.38                                            .................3

form 2 equation

0.165(3.2)sin35 = 0.155(v4)sinθ  

v4 sinθ = 1.95                                              ......................4

so magnitude of another ball velocity is square and adding equation 3 and 4

another ball velocity = √(3.39²+1.96²)

another ball velocity = 3.92 m/s

and direction is tanθ = 1.96/3.39

θ = 30° clockwise from initial direction

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3 years ago
A rock falls off a cliff. How fast is the rock traveling vertically two seconds later?
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The rock it traveling really, really fast.
It is hard to exactly determine how fast bc u need the height of the cliff and how big the rock is.
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3 years ago
Studies of the relationship of the Sun to our galaxy-the Milky Way-have revealed that the Sun is located near the outer edge of
lianna [129]

Mass of the milkyway galaxy :

M_{mw} = \frac{4\pi ^{2}r^{3}}{GT^{2}}\\\\M_{mw} = \frac{4\pi ^{2}(3x10^{4}x9.46x10^{15})^{3}}{6.67x10^{-11}Nm^{2}/Kg^{2}x(7.13x10^{15})^2}\\\\M_{mw } =  2.7x10^{14} Kg

The magnitude of the mass of the Milky Way galaxy = 2.7x10^{14} Kg

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6 0
2 years ago
A 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in
Talja [164]

Answer:

132 N

Explanation:

Given that a  1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail

From Newton 2nd law of motion,

Change in momentum = impulse.

Change in momentum = m( V - U )

Substitute all the parameters into the formula

Change in momentum = 1.1 ( 4.5 - 1.5 )

Change in momentum = 1.1 × 3

Change in momentum = 3.3 kgm/s

Impulse = Ft

That is,

Ft = 3.3

Substitute time t into the formula above

F × 0.025 = 3.3

F = 3.3 / 0.025

F = 132 N

Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.

3 0
3 years ago
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