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Radda [10]
3 years ago
8

Which expression is equivalent to -9x^-1y^-1 / -15x^5 y^-3 Assume x = 0 y = 0

Mathematics
2 answers:
jenyasd209 [6]3 years ago
8 0
For this case we have the following expression:
   -9x ^ -1y ^ -1 / -15x ^ 5 y ^ -3
 For power properties we have:
   -9x ^ (- 1-5) y ^ (- 1 - (- 3)) / - 15
 Rewriting we have:
   9x ^ (- 6) y ^ (- 1 + 3) / 15
   3x ^ (- 6) y ^ (2) / 5
   3y ^ 2 / 5x ^ 6
 Answer:
 
  3y ^ 2 / 5x ^ 6Note: answer is not between the options. Rewrite the expression again, or the options.
tresset_1 [31]3 years ago
5 0
\dfrac{-9x^{-1}y^{-1}}{-15x^5 y^{-3}}\ \ \ \text{assume}\ x\neq0\ \wedge\ y\neq0\\\\\text{Use:}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\\\a^{-n}=\dfrac{1}{a^n}

\dfrac{-9x^{-1}y^{-1}}{-15x^5 y^{-3}}=\dfrac{-9:3}{-15:3}\cdot x^{-1-5}y^{-1-(-3)}=\dfrac{3}{5}\cdot x^{-6}y^{-1+3}\\\\=\dfrac{3}{5}\cdot\dfrac{1}{x^6}\cdot y^2=\boxed{\dfrac{3y^2}{5x^6}}
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5/8 x 10/3 pls help i hate math
gtnhenbr [62]

Answer:

25/12, 2.083, 2 and 1/ 12th

Step-by-step explanation:

PLz mark brainliest

5 0
2 years ago
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What is the ratio of the surface area of a<br>2-inch cube to a 4-inch cube?​
sveta [45]

Answer:

2:4

Step-by-step explanation:

4 0
3 years ago
Given the system of equations, what is the solution? <br><br> x + 2y = 11 <br> x - 2y = -1
zhenek [66]

We need to solve x+2y=11 for x

Let's start by adding -2y to both sides

x+2y -2y = 11-2y

x= -2y+11

Now substitute -2y+11 for x in x-2y =-1

x-2y=-1

-2y+11-2y=-1

-4y+11=-1

Add -11 to both sides

-4y+11-11=-1-11

-4y=-12

Divide both sides by -4

-4y/-4 = -12/-4

y= 3

Substitute 3 for y in x=-2y+11

x= -2y+11

x = (-2)(3)+11

x=-6+11

x=5


The answer is x=5 and y=3

(5,3)


I hope that's help:)



4 0
3 years ago
Phil and Matt made a total of $72.00 selling the cookies. How many cookies
marshall27 [118]

Answer:

36

Step-by-step explanation:

It would only be 36 if they split the amount though

5 0
2 years ago
What are the x– and y–intercepts of the graph of y = 2x^2 – 8x – 10?
Nadya [2.5K]
<u>x-intercepts are found by setting y=0</u>
y=2x^2-8x-10\rightarrow0=2x^2-8x-10
<em>factor out a 2</em> 0=2(x^2-4x-5)\rightarrow0=x^2-4x-5
<em />0=(x-5)(x+1) <em>roots should be </em>x=-1,5
therefore, x-intercepts are (-1,0) and (5,0)
<u>
</u><u>y-intercepts are found by setting x=0</u>
y=2x^2-8x-10\rightarrow y=2(0)^2-8(0)-10
\rightarrow y=0-0-10=-10
therefore, y-intercept is (0,-10)
4 0
3 years ago
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