What is 70.5 and 79.5 on a number line 60-100?

"Jonas prepared himself to walk to the stage when the applause ended and the Chief Elder picked up the next folder and looked do

IceJOKER [234]

Answer:

3rd limited

Step-by-step explanation:

5 0

3 years ago

Evaluate how organizations can use one-sample hypothesis testing to determine if there are performance issues in the organizatio

Margarita [4]

Answer:

Organizations can use one-sample hypothesis test to determine if there are performance issues in many ways.

It can be applied to the performance of a sector, a machine, a product, an advertising campaing, etc.

For example, we can take the example of a machine. It may be claimed that a specific machine performs significantly worse than the average.

This average would be the population mean: the average performance of the machines of the same type or process.

Then, a sample of the performance of the machine in study is taken and the hypothesis test can be performed to test the claim that this machine performs significantly worse.

Step-by-step explanation:

For example, we have an historic performance for this type of machine of 100 units a day. The machine A in study is sampled 14 days and have a performance of 92 units a day, with a sample standard deviation of 12 units/day. We have to test the claim that the machine A makes less units per day than the average.

Then, the null and alternative hypothesis are:

$H_0: \mu=100\\\\H_a:\mu< 100$

The significance level is 0.05.

The sample has a size n=14.

The sample mean is M=92.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{14}}=3.2071$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{92-100}{3.2071}=\dfrac{-8}{3.2071}=-2.4944$

The degrees of freedom for this sample size are:

$df=n-1=14-1=13$

This test is a left-tailed test, with 13 degrees of freedom and t=-2.4944, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0.0134) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that machine A produces significantly less units per day than the average.

3 0

4 years ago

A meuseum had x visitors on friday. On Saturday it had 150 more visitors than it did on friday. The total number of visitors on

ANTONII [103]

Answer:

75 people.

Step-by-step explanation:

If Friday is x, then Saturday is 150 + x. The number of people on Sunday then is (Friday + Saturday)/2, thus (x + (150 + x))/2. This then simplifies to (x + 150 + x)/2 ---> (2x + 150)/2 ---> 2x/2 + 150/2 ---> x + 75. So, Friday is x and Sunday is x + 75, to find out how many more visitors the museum have on Sunday than Friday, you subtract the two numbers. (x + 75) - x = 75.

8 0

4 years ago

Give the equation of the line with a slope of -7/2<br> and a y-intercept of - 6

antoniya [11.8K]

Answer:

$y = \frac{ - 7}{2} - 6$

3 0

3 years ago

An assembly line with 10 tasks needs be designed. The total time for all tasks is 16 minutes. If you need to produce 30 units/ho

Sindrei [870]

Answer: 8 minimum work stations is what would be needed.

Step-by-step explanation:

The cycle time is computed as the operating time daily divided by the scheduled output.

It is important to note that the daily capacity of the operation layout is the operating time divided by the cycle time.

Therefore,

If you need to produce 30units/hour.

The average cycle time is as follow:

The average cycle time is the average time between the completions of units.

60/30= 2 average cycle time

=16/2

=8

8 work stations is the minimum number that would be needed.

It is important to know that in an assembly line balancing, the minimum number of work station is the ratio of the sum of all tasks time to the cycle time.

5 0

3 years ago