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vivado [14]
3 years ago
13

When it is 4:00 a.m. in London, it is 11:00 a.m. in Hanoi. If you leave Hanoi at 7:45 a.m. on Friday and fly to London over the

course of 9 hours and 45 minutes, what time will it be in London when you land? a. 12:30 a.m. Saturday b. 5:30 a.m. Friday c. 10:30 a.m. Friday d. 8:30 a.m. Friday
Mathematics
2 answers:
zalisa [80]3 years ago
8 0

Answer:b

Step-by-step explanation:

Mice21 [21]3 years ago
8 0

Answer:

is d

Step-by-step explanation:

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Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^
Gemiola [76]

Answer:

\rm \displaystyle y' =   2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x}

Step-by-step explanation:

we would like to figure out the differential coefficient of e^{2x}(1+\ln(x))

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

\displaystyle y =  {e}^{2x}  \cdot (1 +   \ln(x) )

to do so distribute:

\displaystyle y =  {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x}

take derivative in both sides which yields:

\displaystyle y' =  \frac{d}{dx} ( {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x} )

by sum derivation rule we acquire:

\rm \displaystyle y' =  \frac{d}{dx}  {e}^{2x}  +  \frac{d}{dx}   \ln(x)  \cdot  {e}^{2x}

Part-A: differentiating $e^{2x}$

\displaystyle \frac{d}{dx}  {e}^{2x}

the rule of composite function derivation is given by:

\rm\displaystyle  \frac{d}{dx} f(g(x)) =  \frac{d}{dg} f(g(x)) \times  \frac{d}{dx} g(x)

so let g(x) [2x] be u and transform it:

\displaystyle \frac{d}{du}  {e}^{u}  \cdot \frac{d}{dx} 2x

differentiate:

\displaystyle   {e}^{u}  \cdot 2

substitute back:

\displaystyle    \boxed{2{e}^{2x}  }

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

\displaystyle  \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)

let

  • f(x) \implies   \ln(x)
  • g(x) \implies    {e}^{2x}

substitute

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =  \frac{d}{dx}( \ln(x) ) {e}^{2x}  +  \ln(x) \frac{d}{dx}  {e}^{2x}

differentiate:

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =   \boxed{\frac{1}{x} {e}^{2x}  +  2\ln(x)  {e}^{2x} }

Final part:

substitute what we got:

\rm \displaystyle y' =   \boxed{2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x} }

and we're done!

6 0
3 years ago
Question 7 of 25 Which of the binomials below is a factor of this trinomial? x - 6x-16 O A. X-1 O B. X-8 OC. X-16 O D. x-2​
kvasek [131]

Answer:

(x-8) is the factor.

Step-by-step explanation:

The given trinomial is x^{2}-6x-16.

We need to find the factor of this trinomial.

x^{2}-6x-16=x^2-8x+2x-16\\\\=x(x-8)+2(x-8)\\\\=(x+2)(x-8)

The factors of x^{2}-6x-16 is (x-2) and (x-8).

So, the factor of x^{2}-6x-16 is (x-8). Hence, the correct option is (B).

5 0
3 years ago
Find the coefficient:
guapka [62]

Answer:

1/3

Step-by-step explanation:

Ask me in the comments of you need an explanation.

:)

3 0
3 years ago
Read 2 more answers
What is the second term of the expression 2x + 3x + 5
mojhsa [17]

Answer:

2x + 3x + 5= 10x

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLEasE i need help brainlist if u get right
Juli2301 [7.4K]

Answer:

c or a i just did the test

Step-by-step explanation:

3 0
3 years ago
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