When tightening a bolt, you push perpendicularly on a wrench with a force of 167 N at a distance of 0.1450 mm from the centre of
1 answer:
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<h2>Answer: its temperature must increase.</h2>
Explanation:
In an isobaric process the pressure remains constant, which means the initial pressure and the final pressure will be the same.
In addition, during this thermodynamic process, the volume of the ideal gas expands or contracts in such a way that the variation of pressure is neutralized.
Now, according to the First law of Thermodynamics that establishes the conservation of energy:
(1)
Where:
is the internal energy
is the heat transferred
is the work
Now, for an isobaric process:
(2)
Where:
is the pressure (<u>always positive</u>)
is the volume variation of the gas
<u />
<u>Here we have two possible results:</u>
-If the gas expands (positive ), the work is positive.
-If the gas compresses (negative ), the work is negative.
In this case we are talking about the first result (work is positive).
Then, according to the above, equation (1) can be written as follows:
(3)
Clearing :
(4)
Then, for an ideal gas in an isobaric process, part of the heat () added to the system will be used to do work (positive in this case) and the other part <u>will increase the internal energy</u>, hence <u>the temperature will increase as well.</u>
Answer:
Electric potential energy at the negative terminal:
Explanation:
When a particle with charge travels across a potential difference
, then its change in electric potential energy is
In this problem, we know that:
The particle is an electron, so its charge is
We also know that the positive terminal is at potential
While the negative terminal is at potential
Therefore, the potential difference (final minus initial) is
So, the change in potential energy of the electron is
This means that the electron when it is at the negative terminal has of energy more than when it is at the positive terminal.
Since the potential at the positive terminal is 0, this means that the electric potential energy of the electron at the negative end is