It would be a) 2 electrons
Answer:
Estimation: year 1110.
Explanation:
We need to know how much time it takes to move 100 arcseconds if it moves at 0.11 arcsecond per year. Similarly to any velocity equation
, where in our case the distances are angular, we will obtain the time by doing:

Which, considering from 2019, the explosion ought to have been observed around 1110 (in reality it was observed by Chinese astronomers in 1054).
Answer:

Explanation:
(The following exercise is written in Spanish and for that reason explanation will be held in Spanish)
Supóngase que el planeta tiene una órbita circular, el período de rotación del planeta es:

Asimismo, la rapidez angular se describe como función de la aceleración centrípeta:

Ahora se reemplaza en la ecuación de período:

La aceleración experimentada por el planeta es:

Se reemplaza en la ecuación de período:

La distancia del planeta con respecto al sol es finalmente despejada:

![R = \sqrt[3]{G\cdot M_{sun}\cdot \left(\frac{T}{2\pi} \right)^{2}}](https://tex.z-dn.net/?f=R%20%3D%20%5Csqrt%5B3%5D%7BG%5Ccdot%20M_%7Bsun%7D%5Ccdot%20%5Cleft%28%5Cfrac%7BT%7D%7B2%5Cpi%7D%20%5Cright%29%5E%7B2%7D%7D)
Finalmente, se sustituyen las variables y se determina la distancia:
![R = \sqrt[3]{\left(6.674\times 10^{-11}\,\frac{N\cdot m^{2}}{kg^{2}} \right)\cdot (1.989\times 10^{30}\,kg)\cdot \left[\frac{(65\,a)\cdot \left(365\,\frac{d}{a} \right)\cdot \left(86400\,\frac{s}{d} \right)}{2\pi} \right]^{2}}](https://tex.z-dn.net/?f=R%20%3D%20%5Csqrt%5B3%5D%7B%5Cleft%286.674%5Ctimes%2010%5E%7B-11%7D%5C%2C%5Cfrac%7BN%5Ccdot%20m%5E%7B2%7D%7D%7Bkg%5E%7B2%7D%7D%20%5Cright%29%5Ccdot%20%281.989%5Ctimes%2010%5E%7B30%7D%5C%2Ckg%29%5Ccdot%20%5Cleft%5B%5Cfrac%7B%2865%5C%2Ca%29%5Ccdot%20%5Cleft%28365%5C%2C%5Cfrac%7Bd%7D%7Ba%7D%20%5Cright%29%5Ccdot%20%5Cleft%2886400%5C%2C%5Cfrac%7Bs%7D%7Bd%7D%20%5Cright%29%7D%7B2%5Cpi%7D%20%5Cright%5D%5E%7B2%7D%7D)


Solution
Force between pair of objects of masses 1kg and 2kg that are 1m apart is given as

here G is gravitational constant
G=
therefore,


similarly Force between pair of objects of masses 2kg each that are 1m apart is given as



or F'=2F
it means Force between pair of objects of masses 2kg each that are 1m apart is equal to twice the Force between pair of objects of masses 1kg and 2kg that are 1m
Answer:
Alright, I will, and thank you for the brainliest!
Explanation: