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Katena32 [7]
3 years ago
15

All of the following could describe an individual with antisocial personality disorder except __________. A. impulsive B. manipu

lative C. aggressive D. responsible Please select the best answer from the choices provided A B C D
Physics
1 answer:
Natali5045456 [20]3 years ago
7 0

D. responsible

Explanation:

Individuals with antisocial personality disorder are not responsible. They are often aggressive, impulsive and quite manipulative.

Antisocial personality disorder is a mental disorder in which a person violates the rights of others without feeling any remorse for doing so.

  • People with such disorders have a high tendency of breaking rules and laws in the society.
  • They are often manipulative and tends to make the society favor them.
  • They carryout activities without a forethought i.e impulsive.
  • They live a chaotic and irresponsible life feeling not duty bound to the society.
  • People with this disorder can be aggressive too.

Often times, this problem can be remedied by therapy

learn more:

Psychological disorder brainly.com/question/4211983

#learnwithBrainly

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At a certain temperature, the rate constant for this reaction is 5.64×10−4 s−1 . Calculate the half-life of cyclopropane at this
oee [108]

Answer:

t_{1/2}= 20.47\ minute

Explanation:

given,

constant rate for the reaction(k) =  5.64  ×  10⁻⁴ s⁻¹

to calculate the half life  = ?

t_{1/2} = \dfrac{0.693}{k}

t_{1/2} = \dfrac{0.693}{5.64\times 10^{-4}}

on solving the above equation

t_{1/2} = 1228.72 s

t_{1/2} = \dfrac{1228.72}{60}

t_{1/2}= 20.47\ minute

hence, the half-life of cyclopropane at this temperature =t_{1/2}= 20.47\ minute

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3 years ago
Running water has materials such as dirt, sand, and dead plants and animals in it. When this water ends up in a lake, the materi
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The outside layer is the wettest.

Explanation:

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2 years ago
Which best explains parallel forces?
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The answer is to this question is B
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How many protons does the largest transition metal have in its nucleus?
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3 years ago
66. Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, and (d) 2.00 s for a ball thrown st
kozerog [31]

Answer:

a) t=1s

y = 10.1m

v=5.2m/s

b) t=1.5s

y =11.475 m

v=0.3m/s

c) t=2s

y =10.4 m

v=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

Explanation:

Conceptual analysis

We apply the free fall formula for position (y) and speed (v) at any time (t).

As gravity opposes movement the sign in the equations is negative.:  

y = vi*t - ½ g*t2 Equation 1

v=vit-g*t  Equation 2

y: The vertical distance the ball moves at time t  

vi: Initial speed

g= acceleration due to gravity

v= Speed the ball moves at time t  

Known information

We know the following data:

Vi=15 m / s

g =9.8 \frac{m}{s^{2} }

t=1s ,1.5s,2s

Development of problem

We replace t in the equations (1) and (2)  

a) t=1s

y = 15*1 - ½ 9.8*1^{2}=15-4.9=10.1m

v=15-9.8*1 =15-9.8 =5.2m/s

b) t=1.5s

y = 15*1.5 - ½ 9.8*1.5^{2}=22.5-11.025=11.475 m

v=15-9.8*1.5 =15-14.7=0.3m/s

c) t=2s

y = 15*2 - ½ 9.8*2^{2}= 30-19.6=10.4 m

v=15-9.8*2 =15-19.6=-4.6m/s  (The minus sign (-) indicates that the ball is already going down)

3 0
3 years ago
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