A quantity with an initial value of 9100 grows continuously at a rate of 0.85% per hour. What is the value of the quantity after
22 hours, to the nearest hundredth?
1 answer:
Answer:
![10,962,54](https://tex.z-dn.net/?f=10%2C962%2C54)
Step-by-step explanation:
we know that
The equation of a exponential growth is equal to
![y=a(1+r)^x](https://tex.z-dn.net/?f=y%3Da%281%2Br%29%5Ex)
where
a is the initial value
r is the rate of growth
x is the time in hours
y is the value of the quantity
we have
![a=9,100\\r=0.85\%=0.85/100=0.0085](https://tex.z-dn.net/?f=a%3D9%2C100%5C%5Cr%3D0.85%5C%25%3D0.85%2F100%3D0.0085)
substitute
![y=9,100(1+0.0085)^x](https://tex.z-dn.net/?f=y%3D9%2C100%281%2B0.0085%29%5Ex)
![y=9,100(1..0085)^x](https://tex.z-dn.net/?f=y%3D9%2C100%281..0085%29%5Ex)
For x=22 hours
substitute
![y=9,100(1..0085)^{22} =10,962,54](https://tex.z-dn.net/?f=y%3D9%2C100%281..0085%29%5E%7B22%7D%20%3D10%2C962%2C54)
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122 po yan po dapat
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thanks me letter