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2 years ago

How would I workout question 4?? Please help

Physics

1 answer:

Agata [3.3K]2 years ago

3 0

Answer:

550 kg

Explanation:

mass = E / gh

= 33000/60

=550

plzzz......

mark it as a brilliant answer

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What is a characteristic of physics that astrology does not have?

katrin2010 [14]

Think about it, in physics, it has theories or something that people believe astrology basically consists of MYTHOLOGY and it could also be correct with predictions. Astrology doesnt have actual answers for any type of questions

Hope this helped...

8 0

2 years ago

To test the performance of its tires, a car

velikii [3]

Answer:

The coefficient of static friction between the tires and the road is 1.987

Explanation:

Given:

Radius of the track, r = 516 m

Tangential Acceleration $a_r$ = 3.89 m/s^2

Speed,v = 32.8 m/s

To Find:

The coefficient of static friction between the tires and the road = ?

Solution:

The radial Acceleration is given by,

$a_{R = \frac{v^2}{r}$

$a_{R = \frac{(32.8)^2}{516}$

$a_{R = \frac{(1075.84)}{516}$

$a_{R = 2.085 m/s^2$

Now the total acceleration is

$\text{ total acceleration} = \sqrt{\text{(tangential acceleration)}^2 +{\text{(Radial acceleration)}^2$

=> $= \sqrt{ (a_r)^2+(a_R)^2}$

=> $\sqrt{ (3.89 )^2+( 2.085)^2}$

=> $\sqrt{ (15.1321)+(4.347)^2}$

=> $19.4791 m/s^2$

The frictional force on the car will be f = ma------------(1)

And the force due to gravity is W = mg--------------------(2)

Now the coefficient of static friction is

$\mu =\frac{f}{W}$

From (1) and (2)

$\mu =\frac{ma}{mg}$

$\mu =\frac{a}{g}$

Substituting the values, we get

$\mu =\frac{19.4791}{9.8}$

$\mu =1.987$

8 0

3 years ago

A box of mass m is held at rest on a frictionless surface with force F up the ramp. The ramp has an angle

frutty [35]

Answer:

Explanation:

8 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST

Komok [63]

Answer:

yes every action as an equal and and opposite reaction. if you throw a tool then it will give you a reaction and you will move back.

Explanation:

According to Newton's third law of motion, when two bodies interact between them, appear equal forces and opposite senses in each of them.

To understand it better:

Each time a body or object exerts a force on a second body or object, it (the second body) will exert a force of equal magnitude but in the opposite direction on the first.

So, if you as an astronaut in the described situation throw your tool in the direction that you are traveling (in the opposite direction of the space station), according to Newton's third law, you will be automatically moving towards the station

6 0

2 years ago

3.1

Ilia_Sergeevich [38]

Answer:

The value is $C = 30729\ c$