1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irga5000 [103]
3 years ago
14

Paul lifts a sack weighing 245 newtons vertically from the ground and places it on a platform at a height of 0.7 meters. If he t

akes 10 seconds to do this task, what power has he expended during this time? A. 10 watts B. 17.15 watts C. 23.6 watts D. 29.8 watts
Physics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:

B. 17.15 watts

Explanation:

Given that

Time = 10 seconds

height = distance = 0.7 meters

weight of sack = mg = F = 245 newtons

Power = work done/ time taken

Where work done = force × distance

Substituting the given parameters into the formula

Work done = 245 newton × 0.7 meters

Work done = 171.5 J

Recall,

Power = work done/time

Power = 171.5 J ÷ 10

Power = 17.15 watts

Hence the power expended is B. 17.15 watts

You might be interested in
One scientist is using an electromagnetic wave to map the dust between stars. The electromagnetic wave has shorter wavelength th
m_a_m_a [10]
Infrared light

it is also found under the name IR lights. although it’s technically invisible, it can still be seen with machinery up to at least 1050 nm in experiments.
3 0
3 years ago
¿Cuál es la aceleración centrípeta de un móvil que recorre una
Lady bird [3.3K]

Answer:

a)  a = 4.57 m/s², b)  a = 6.48 m / s² , c)  a = 1.42 m / s²,d)   r = 82.3 m

 

Explanation:

The centripetal acceleration is the acceleration responsible for the change of direction of the acceleration vector and occurs in circular movements, the expression is

           a = v² / r

let's apply this precaution to our cases

a) let's calculate

          a = 8²/14

         a = 4.57 m/s²

b) an automobile at v = 65 km / h (1000 m / 1km) (1 h / 3600 s) =18,055 m/s

let's reduce feet to meters

          1 ft = 0.3048 m

           r = 165 ft (0.3048 m / 1 ft) = 50.292 m

          a = 18,055 2 / 50,292

           a = 6.48 m / s²

c) we calculate

          a = 1.25²2 / 1.1

          a = 1.42 m / s²

d) we look for the radius

          a = v² / r

          r = v² / a

we reduce

          v = 80 km / h (1000 m / 1km) (1h / 3600s) = 22.22  ms

          r = 22.22²/6

          r = 82.3 m

e) the cenripeta acceleration is used to take the curves on the highway,

    Used in centrifuges to separate compounds

       It is used in the games of the park of atraccio

     Used in CD players and computer hard drives

5 0
3 years ago
A package of aluminum foil contains 50. Ft2 of foil, which weighs approximately 7.0 oz . Aluminum has a density of 2.70 g/cm3. W
kumpel [21]

We know density = Mass / Volume

So Volume = Mass/Density

Volume =  Area * Thickness

Area = 50 ft^2 = 4.645152 m^2\\ \\Mass = 7 oz = 0.198447 kg\\ \\Density = 2.70 g/cm^3 = 2700 kg/m^3\\ \\Substituting \\ \\4.645152 *t = \frac{0.198447}{2700} \\ \\t = 1.58*10^{-5}m = 1.58*10^{-2}mm

So the approximate thickness of the foil in millimeters = 1.58*10^{-2}mm

6 0
4 years ago
a large parallel plate capacitor has plate seperation of 1.00 cm and plate area of 314 cm^2. The capacitor is connected across a
Whitepunk [10]

Answer:

W = -2.76\times 10^{-9}~J

Explanation:

The work done on the capacitor is equal to the difference in potential energy stored in the capacitor in two different cases.

The potential energy is given by the following formula:

U = \frac{1}{2}CV^2

where C can be calculated using the plate separation and area.

C = \epsilon\frac{A}{d} = \epsilon\frac{0.0314}{0.01} = 3.14\epsilon

Therefore, the potential energy in the first case is

U = \frac{1}{2}3.14\epsilon (20)^2 = 628\epsilon

In the second case:

C_2 = \epsilon\frac{A}{d} = \epsilon\frac{0.0314}{0.02} = 1.57\epsilon\\U = \frac{1}{2}C_2 V^2 = \frac{1}{2}1.57\epsilon (20)^2 = 314\epsilon

The permittivity of the air is very close to that of vacuum, which is 8.8 x 10^-12.

So, the difference in the potential energy is

W = U_2 - U_1 = \epsilon(314 - 628) = -314 \times 8.8 \times 10^{-12} = -2.76\times 10^{-9}~J

6 0
3 years ago
Please help me with this question,giving the first correct answer brainliest
Bess [88]

Answer:

Your answer is A

Explanation:

7 0
2 years ago
Read 2 more answers
Other questions:
  • What is any factor of an experiment that is not changed called? control, dependent variable ,independent variable
    7·2 answers
  • Hellllppppppp please
    9·1 answer
  • Why are certain metalloids useful in today's technological equipment?
    6·1 answer
  • Which statement correctly identifies a difference between the function of most arteries and veins?
    13·1 answer
  • A hydraulic cylinder is to compress a car body down to bale size in 30 sec. The operation requires a 25 ft stroke and a 9500-lb
    7·1 answer
  • Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.
    6·1 answer
  • A total charge of 4.70 is distributed on two metal spheres. When the spheres are 10 cm apart, they each feel a repulsive force o
    8·1 answer
  • Como surgiu a capoeira?
    9·1 answer
  • Can someone please help me with this one
    14·1 answer
  • Please who can give me the definition of density in terms of Archimedes principle.​
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!