Paul lifts a sack weighing 245 newtons vertically from the ground and places it on a platform at a height of 0.7 meters. If he t
1 answer:
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Answer:
H = 34.43 m
Explanation:
Given that,
Initial speed of the object, u = 30 m/s
The angle of projection,
We need to find the maximum height reached by the object. Let it is H. Using the formula for maximum height reached by the projectile.
So, the maximum height reached by the object is 34.43 m.
Answer:
Part(a): The frequency is .
Part(b): The speed of the wave is .
Explanation:
Given:
The distance between the crests of the wave, .
The time required for the wave to laps against the pier,
The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is .
Also, the time required for the wave for each laps is the time period of oscillation and it is given by .
Part(a):
The relation between the frequency and time period is given by
Substituting the value of in equation (1), we have
Part(b):
The relation between the velocity of a wave to its frequency is given by
Substituting the value of and
in equation (2), we have