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3 years ago

15

Hey can someone send me the answer to this

1 answer:

bagirrra123 [75]3 years ago

5 0

Cars 'A' and 'C' look like they're moving at the same speed. If their tracks are parallel, then they're also moving with the same velocity.

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HEY CAN ANYONE PLS PLS ANSWER DIS I RLY NEED IT

jeka94

Place the object in an electronic balance and measure its mass.
Place a measured amount of water in the cylinder.
Place the object in the cylinder so that it’s fully submerged.
Measure the new level of the liquid and subtract the original level. This is equal to the volume of the object.

Density = mass / volume.

8 0

3 years ago

Scientists in a test lab are testing the hardness of a surface before constructing a building. Calculations indicate that the en

Over [174]

It depends on what that "certain amount" is.

7 0

3 years ago

The table provided shows the masses and volumes of four liquids. A student has a mystery liquid with a density of 3 g/mL. Which

Aleonysh [2.5K]

Answer: Liquid 2, if it's 3 g/mL and liquid 2 has 6gs and 2 mLs than it's 3g/mL

8 0

3 years ago

What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 20.0 km/h?

Tanya [424]

Answer:

The minimum coefficient of friction is 0.22

Explanation:

Suppose If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve.

We need to calculate the ideal speed to take a 85 m radius curve banked at 15°.

Given that,

Radius = 85 m

Angle = 15°

Speed = 20 km/h

We need to calculate the ideal speed

Using formula of speed

$\tan\theta=\dfrac{v^2}{rg}$

$v=\sqrt{rg\tan\theta}$

Put the value into the formula

$v=\sqrt{85\times9.8\tan15}$

$v=14.9\ m/s$

We need to calculate the minimum coefficient of friction

Using formula for coefficient of friction

$v^2=\dfrac{rg(\sin\theta-\mu\cos\theta)}{\mu\sin\theta+\cos\theta}$

Put the value into the formula

$(5.55)^2=\dfrac{85\times9.8(\sin15-\mu\cos15)}{\mu\sin15+\cos15}$

$\dfrac{30.8025}{85\times9.8}=\dfrac{0.2588-\mu0.966}{\mu0.2588+0.966}$

$0.9754462\ mu-0.223541=0$

$\mu=\dfrac{0.223541}{0.9754462}$

$\mu=0.22$

Hence, The minimum coefficient of friction is 0.22

3 0

3 years ago

A 10-kilogram mass is sliding along a frictionless floor with an acceleration of 5 meters per second squared. What is the magnit

Darina [25.2K]

Answer:

50N

Explanation:

Since the floor is frictionless, the net force = mass × acceleration.

given that,

mass = 10kg

and acceleration is 5 m/s²

Thus,

Force = 10 × 5

Force = 50 N

5 0

3 years ago