Answer: Your question is missing below is the question
Question : What is the no-friction needed speed (in m/s ) for these turns?
answer:
20.1 m/s
Explanation:
2.5 mile track
number of turns = 4
length of each turn = 0.25 mile
banked at 9 12'
<u>Determine the no-friction needed speed </u>
First step : calculate the value of R
2πR / 4 = πR / 2
note : πR / 2 = 0.25 mile
∴ R = ( 0.25 * 2 ) / π
= 0.159 mile ≈ 256 m
Finally no-friction needed speed
tan θ = v^2 / gR
∴ v^2 = gR * tan θ
v = √9.81 * 256 * tan(9.2°) = 20.1 m/s
Answer:
Option B is the correct answer.
Explanation:
Let us consider 40 meter above ground as origin.
Initial velocity = 17 m/s
Final velocity = 24 m/s
Acceleration = 9.81 m/s
We have equation of motion v² = u² + 2as
Substituting
24² = 17² + 2 x 9.81 x s
s = 14.63 m
Distance traveled by rock = 14.63 m down.
Height of rock from ground = 40 - 14.63 = 25.37 m = 25.4 m
Option B is the correct answer.
Let's calculate the total charge of M=4.8 g=0.0048 kg of protons.
Each proton has a charge of

, and a mass of

. So, the number of protons is

And so the total charge of these protons is

So, the neutralize this charge, we must have

electrons such that their total charge is

Since the charge of each electron is

, the number of electrons needed is

which is the same as the number of protons (because proton and electron have same charge magnitude). Since the mass of a single electron is

, the total mass of electrons should be
Answer:
A frame of reference is the location from which motion is perceived and measured. For all observers, the speed of light remains constant.
Explanation: