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ella [17]
3 years ago
8

Some one please help me!!!!!!!

Physics
1 answer:
inn [45]3 years ago
6 0

D) 25N!

Under the term we have work (100J) and movement of the subject (4m).

You should find force:

A=F*s

F=A/s

F=100/4

F=25 N

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Answer:

I = 4.189 mA    V = 0.338 V

Explanation:

In order to do this, we need to apply the following expression:

I = Is[exp^(qV/kT) - 1]   (1)

However, as the junction of the diode is illuminated, the above expression changes to:

I = Iopt + Is[exp^(qV/kT) - 1]   (2)

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I ≅ Iopt

Therefore:

I ≅ I₀Aλq / hc  (3)

Where:

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λ: wavelength

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h: Planck constant (6.62x10⁻³⁴ m² kg/s)

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Replacing all these values, we can get the current:

I = (8x10⁻³) * (0.65x10⁻⁶) * (1.6x10⁻¹⁹) / (6.62x10⁻³⁴) * (3x10⁸)

I = 4.189x10⁻³ A or 4.189 mA

Now that we have the current, we just need to replace this value into the expression (2) and solve for the voltage:

I = Is[exp^(qV/kT) - 1]

k: boltzman constant (1.38x10⁻²³ J/K)

4.189x10⁻³ = 9x10⁻⁹ [exp(1.6x10⁻¹⁹ V / 1.38x10⁻²³ * 300) - 1]

4.189x10⁻³ / 9x10⁻⁹ = [exp(38.65V) - 1]

465,444.44 + 1  = exp(38.65V)

ln(465,445.44) = 38.65V

13.0508 = 38.65V

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