Help me pretty please

1.)Describe an experience where you encountered a buoyant force and tell what it felt like.

kap26 [50]

Swimming: Knowing I would not sink made feel safe.

Taking off in an aircraft: I felt heavier.

Explanation:

The buoyant force originates from the weight applied to the item by the liquid. Since the weight increments as the profundity press, the base of an article are constantly bigger than the power on the top - consequently the net upward power.

It follows up on an article inverse to gravity by liquid which is being submerged mostly or totally in the liquid. It contradicts the heaviness of the item. The buoyant force is given by volume dislodged by an item into the thickness of liquid into gravitational quickening.

8 0

3 years ago

If velocity is 0.2m/s, what is the kinetic energy?

Natalija [7]

$\huge\boxed{♧ \: \mathfrak{ \underline{Answer} \: ♧}}$

we know,

$\boxed{kinetic \: \: energy = \frac{1}{2} m {v}^{2} }$

So,

$\longmapsto \dfrac{1}{2} \times 10 \times 0.2 \times 0.2$

$\longmapsto0.2 \: joules$

3 0

3 years ago

Can all waves be distorted, deflected, or changed? Explain your response.

kow [346]

Yes, all waves can be distorted, deflected, or changed

Waves are a means by which energy travels. Many different particles move in waves. All waves can be changed through interference with waves of similar wavelengths.

8 0

3 years ago

What frequency is received by the ambulance after reflecting from a wall near the person watching the oncoming ambulance (as in

ElenaW [278]

Answer:

f=896Hz

Explanation:

Given data

Vs(speed of the ambulance)={(104 km/h)*(1000m*(1 h/3600)}=28.9m/s

f(frequency of the ambulance siren)=821 Hz

v(speed of sound)=345 m/s

Vo(speed of the observer)=0 m/s

To find

f(The ambulance is approaching the person)

Solution

From Doppler effect

$f^{i}=(\frac{v+v_{o} }{v-v_{s} })f$

As the ambulance approaches the we assign a positive sign for speed "vs" of the ambulance

So

$f^{i}=(\frac{v+0}{v-(+v_{s}) } )f\\f^{i}=(\frac{v}{v-v_{s} } )f$

Substitute the values from given data

$f^{i}=(\frac{345m/s}{345m/s-28.9m/s} )821Hz\\f^{i}=896Hz$

5 0

3 years ago

A sample of 20.0 moles of a monatomic ideal gas (γ = 1.67) undergoes an adiabatic process. The initial pressure is and the initi

Alexeev081 [22]

There are some missing data in the text of the exercise. Here the complete text:
"A sample of 20.0 moles of a monatomic ideal gas (γ = 1.67) undergoes an adiabatic process. The initial pressure is 400kPa and the initial temperature is 450K. The final temperature of the gas is 320K. What is the final volume of the gas? Let the ideal-gas constant R = 8.314 J/(mol • K). "

Solution:

First, we can find the initial volume of the gas, by using the ideal gas law:
 $pV=nRT$
where
p is the pressure
V the volume
n the number of moles
R the gas constant
T the absolute temperature

Using the initial data of the gas, we can find its initial volume:
 $V_i = \frac{nRT_i}{p_i} = \frac{(20.0 mol)(8.31 J/molK)(450 K)}{4 \cdot 10^5 Pa} =0.187 m^3$

Then the gas undergoes an adiabatic process. For an adiabatic transformation, the following relationship between volume and temperature can be used:
 $TV^{\gamma-1} = cost.$
where $\gamma=1.67$ for a monoatomic gas as in this exercise. The previous relationship can be also written as
$T_i V_i^{\gamma-1} = T_f V_f^{\gamma-1}$
where i labels the initial conditions and f the final conditions. Re-arranging the equation and using the data of the problem, we can find the final volume of the gas:
$V_f = V_i \sqrt[\gamma-1]{ \frac{T_i}{T_f} }=(0.187 m^3) \sqrt[0.67]{ \frac{450 K}{320 K} }=0.310 m^3 = 310 L$
So, the final volume of the gas is 310 L.

5 0

3 years ago