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jeka94
3 years ago
6

It turns out that the depth in the ocean to which airborne electromagnetic signals can be detected grows with the wavelength. Th

erefore, the military got the idea of using very long wavelengths corresponding to about 30 Hz to communicate with submarines throughout the world. If we want to have an antenna that is about one-half wavelength long, how long would that be
Physics
1 answer:
r-ruslan [8.4K]3 years ago
3 0

Wavelength = speed / frequency.

Wavelength = 3x10^8 m/s / 30 hz

Wavelength = 10 million meters

1/2 wavelength = 5 million meters

(that's about 3,100 miles)

I'm pretty sure the frequency is wrong in the question.

I think it's actually 30 kHz, not 30 Hz.

That makes the antenna about 3.1 miles long.

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maxonik [38]

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Explanation:

Given

mass of wagon m=5 kg

elevation

\theta =30.9^{\circ}\\F=150\ N

Sin component of weight will oppose the applied force therefore we can write

F-W\sin \theta=ma\\where\\W=weight(mg)\\a=acceleration

150-5\times 9.8\times \sin (30.09)^{\circ}=5\times a\\125.43=5a\\a=25.08\ m/s^2

6 0
3 years ago
Three charges 1.5*10-6, 3*10-6, -3*10-6 are placed at three vertices of an equilateral triangle of side 30cm. Find the net force
gulaghasi [49]

Answer:

F = 0N

Explanation:

The force between two charges is given by

F=k\frac{q_1q_2}{r^2}

where r is the distance between the charges and K is the Coulomb's constant

(k=8-89*10^9Nm^2/C^2)

The force in the first charge is only the sum of the forces due to the other charges. Hence we have

F_T=F_1+F_2=k\frac{q_2q_1}{r^2}+k\frac{q_3q_1}{r^2}

F_T=(8.89*10^9\frac{Nm^2}{C^2})\frac{(3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}+(8.89*10^9\frac{Nm^2}{C^2})\frac{(-3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}\\\\F_T=0.445N-0.445N=0N

Ft=0N

Hope this helps!!

5 0
3 years ago
Read 2 more answers
A hot metal washer is placed in a jar of cool water.
ipn [44]
The answer is Conduction: the process of heat is directly transmitted through a substance when there is a difference in temperature.
8 0
3 years ago
A thick window pane 0.367 cm has an area of 1.247 square meters. The temperature difference between the inside and outside surfa
____ [38]

Answer:

B. 9025 J/s

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area (A) = 1.247 m^{2}

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thermal conductivity (K) = 0.8 J/s/m/°C

find the rate of heat flow

rate of heat flow = \frac{K.A.ΔT}{d}

rate of heat flow = \frac{0.8x1.247x33.2}{0.00367}

rate of heat flow = 9024.6 ≈ 9025 J/s

7 0
3 years ago
Explain how the CS, US, CR, and UR relate to the end result?
MakcuM [25]

This is not easy.  We don't know what CS, US, CR, or UR is, and we don't know the end result.  Basically, we have no clue.  This question has to get pitched into the "No given information" bucket.

4 0
3 years ago
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