The relationship between the two is that air temperature changes the air pressure. For example, as the air warms up the molecules in the air become more active and they use up more individual space even though there is the same<span> number of molecules. This causes an </span>increase<span> in the air pressure.</span>
Answer:
ρ_c < ρ_gold the crown is not gold
Explanation:
For this exercise we use the translational equilibrium condition
∑ F = 0
in the air
T₁ - W = 0
T₁ = W
in water
T + B - W = 0
where T is the scale reading, B the liquid thrust and W the weight
B = W -T
B = 7.84 - 6.84
B = 1 N
thrust is
B = ρ g V_water
V_water =
V_water =
V_water = 1.02 10⁻⁴ m³
how the crown is totally submerged
V_c = V_water
V_c = 1.02 10⁻⁴ m³
now we can calculate the density of the crown
ρ_c = m_c / Vc
W = mg
m = W / g
we substitute
ρ_c = 
ρ_c =
ρ_c = 0.784 10⁴ kg / m³
ρ_c = 7.84 10³ kg / m³
We can see that this density is less than the density of gold
ρ_c < ρ_gold
therefore the crown is not gold