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aleksklad [387]
3 years ago
5

Can yall please help!!

Physics
1 answer:
andreyandreev [35.5K]3 years ago
7 0

The compasses would start point towards the wire. When you have a current going through wire it messes with the electrical field and messes up the compasses so they point towards the wire.

Hope this helps!

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Anyone know what type of circuit this is?
Oksana_A [137]

Answer:

C

Explanation:

BECAUSE ITS GOING ON AND ON IF ITS NOT CORRECT I WILL VOTE YOU BRAINLEST ON MY QUESTION

3 0
3 years ago
A 70.0-kg person throws a 0.0430-kg snowball forward with a ground speed of 32.0 m/s. A second person, with a mass of 58.5 kg, c
Aleks04 [339]

Answer:

The velocities of the skaters are v_{1} = 3.280\,\frac{m}{s} and v_{2} = 0.024\,\frac{m}{s}, respectively.

Explanation:

Each skater is not under the influence of external forces during process, so that Principle of Momentum Conservation can be used on each skater:

First skater

m_{1} \cdot v_{1, o} = m_{1} \cdot v_{1} + m_{b}\cdot v_{b} (1)

Second skater

m_{b}\cdot v_{b} = (m_{2}+m_{b})\cdot v_{2} (2)

Where:

m_{1} - Mass of the first skater, in kilograms.

m_{2} - Mass of the second skater, in kilograms.

v_{1,o} - Initial velocity of the first skater, in meters per second.

v_{1} - Final velocity of the first skater, in meters per second.

v_{b} - Launch velocity of the meter, in meters per second.

v_{2} - Final velocity of the second skater, in meters per second.

If we know that m_{1} = 70\,kg, m_{b} = 0.043\,kg, v_{b} = 32\,\frac{m}{s}, m_{2} = 58.5\,kg and v_{1,o} = 3.30\,\frac{m}{s}, then the velocities of the two people after the snowball is exchanged is:

By (1):

m_{1} \cdot v_{1, o} = m_{1} \cdot v_{1} + m_{b}\cdot v_{b}

m_{1}\cdot v_{1,o} - m_{b}\cdot v_{b} = m_{1}\cdot v_{1}

v_{1} = v_{1,o} - \left(\frac{m_{b}}{m_{1}} \right)\cdot v_{b}

v_{1} = 3.30\,\frac{m}{s} - \left(\frac{0.043\,kg}{70\,kg}\right)\cdot \left(32\,\frac{m}{s} \right)

v_{1} = 3.280\,\frac{m}{s}

By (2):

m_{b}\cdot v_{b} = (m_{2}+m_{b})\cdot v_{2}

v_{2} = \frac{m_{b}\cdot v_{b}}{m_{2}+m_{b}}

v_{2} = \frac{(0.043\,kg)\cdot \left(32\,\frac{m}{s} \right)}{58.5\,kg + 0.043\,kg}

v_{2} = 0.024\,\frac{m}{s}

5 0
3 years ago
Two 60 cm parallel disks are separated by 40 cm and are aligned directly on top of each other. Both disks are black surfaces wit
Crazy boy [7]

Answer:

775.48 W

Explanation:

given,

diameter of disk = 0.6 cm

length of the disk = 0.4 m

T₁ = 450 K         T₂ = 450 K      T₃ = 300 K

\dfrac{d}{r_1}=\dfrac{0.4}{0.3} = 1.33

now,

the value of view factor (F₁₂)corresponding to 1.33

F₁₂ = 0.265

F₁₃ = 1 - 0.265 = 0.735

now,

net rate of radiation heat transfer from the disk to the environment:

=\dot{Q_{1-3}+Q_{2-3}} = 2 \dot{Q_{1-3}}

       = 2 F₁₃ A₁ σ (T₁⁴ - T₃⁴)

       = 2 x 0.735 x π x (0.3)² x (5.67 x 10⁻⁸ W/m²) (450⁴ - 300⁴)

       = 775.48 W

Net radiation heat transfer from the disks to the environment = 775.48 W

3 0
4 years ago
A student of mass 60.0 kg, starting at rest, slides down a slide 20.0 m long, tilted at an angle of 30.0° with respect to the ho
cricket20 [7]

Answer:

Explanation:

Reaction force of inclined surface

R = mgcos30

=60 x 9.8 x .866

= 509 N

Force of kinetic friction

= .12 x 509

= 61.08 N

b )

net force downwards = mgsinθ - μmgcosθ

acceleration = g sinθ - μgcosθ

9.8 sin30 - .12 x 9.8 x cos30

= 4.9 - 1.018

a= 3.88 m /s²

c )

v² = 2as

= 2 x  3.88 x 20

v = 12.46 m /s

8 0
3 years ago
Mining would be classified as a _____ human activity for the environment. Negative or positive
Lena [83]

Answer: negative

Explanation:

3 0
3 years ago
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