Answer:
v₂ = 63.62 m / s
Explanation:
For this exercise in fluid mechanics we will use Bernoulli's equation
P₁ + ρ g v₁² + ρ g y₁ = P₂ + ρ g v₂² + ρ g y₂
where the subscript 1 refers to the inside of the wing and the subscript 2 to the top of the wing.
We will assume that the distance between the two parts is small, so y₁ = y₂
P₁-P₂ = ρ g (v₂² - v₁²)
pressure is defined by
P = F / A
we substitute
ΔF / A = ρ g (v₂² - v₁²)
v₂² = 
suppose that the area of the wing is A = 1 m²
we substitute
v₂² = 
v₂² = 79.10 + 3969
v₂ = √4048.1
v₂ = 63.62 m / s
Answer:
no deflection and net force is zero. Moving in same direction and with same speed
Explanation:
Charge = negative
the angle between the velocity vector and the magnetic field vector is 0°, so the force is given by
F = q v B Sin 0
F = 0
As the force is zero so the charge particle moves with the same velocity and in the same direction.
there is no deflection in the path of negatively charged particle.
An example of something that is not a proton would be an electron. It has a negative charge and has a charge of 1.6X10^-19 Coulombs.
Answer:
False
Explanation:
Gravity force is constant.
There some places on Earth that gravity has a variation, but in general, it is the same everywhere.
If you analyze the equation for the weight, which is the action of the gravity to mass, you'll see that W=mg, where m is the mass and g, is gravity.
If you increase the mass, what you are increasing is weight and not gravity.
Answer:
fo = 378.52Hz
Explanation:
Using Doppler effect formula:
where
f' = 392 Hz
C = 340m/s
Vb = 20m/s
Va = 31m/s
Replacing these values and solving for fo:
fo = 378.52Hz
