3 years ago

I need help with #11

1 answer:

4 0

You can plug in the numbers
1) (0,3):
3 < 2(0) + 2
3 < 2 this is incorrect, so it is not 1

2) (2,0)
0 < 2(2) + 2
0 < 6 this passed the first one

0 > -(2) - 1
0 > -3 this is also correct

the answer is 2) (2,0)

You might be interested in

Given the following image, find the angle of rotation and the number of times each figure can rotate.

Dmitriy789 [7]

Rotated: The figure can be rotated 2 times. Angle of Rotation: 180 ∘

7 0

3 years ago

In a complete sentence, describe the positions of these numbers on the number line in relation to each other. Then, write an ine

Tasya [4]

Answer:

ussugdfxysuwneuduchske

7 0

3 years ago

(1/4)^3z-1 =16^z+2*64^z-2<br><br> Z=___<br><br> Please help

wariber [46]

Answer:

Z = 0.198877274

Step-by-step explanation:

$(\frac{1}{4})^{3z-1} = 16^z + 2*16^{z-2}\\4^{1-3z} = 4^{2z} + 4^{\frac{1}{2}}*4^{2z-4}\\4^{1-3z} = 4^{2z} + 4^{2z-4+\frac{1}{2}}\\4^{1-3z} = 4^{2z} + 4^{2z-\frac{7}{2}}\\4^{1-3z} = 4^{2z} *(1+ 4^{-\frac{7}{2}})\\4^{1-3z} = 4^{2z} *(1+ 2^{-7})\\4^{1-3z} = 4^{2z} *(1+ \frac{1}{128} )\\4^{1-3z} = 4^{2z} *(\frac{129}{128} )\\Taking\;\; Logarithm\;\; with\;\; base\;\; 4\\Log_4(4^{1-3z}) = Log_4(4^{2z}) + Log_4(\frac{129}{128})\\1-3z = 2z + 0.005613627712 \\5z = 0.994386372\\z = 0.198877274$