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SashulF [63]
3 years ago
14

What is another problem that could be solved using the expression 9.5•(8+12.5)

Mathematics
1 answer:
Lelu [443]3 years ago
4 0
Another problem you could solve in this equation is inside the perenthisis so it would be 8+12.5
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3q(p-q)+2r(p-q)-S(q-p)<br> Can u solve it step by step
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in the right place possibly

-3q² + 3qp + 2rp - 2rq + Sq - Sp

8 0
2 years ago
A van and a bicycle move towards each other. The speed of the van is 80 km per hour, and the speed of the bike is 20 km per hour
otez555 [7]

:

.

-- :

Bike > ________300km_________< Van

20km/h 80km/h

In one hour, the bike will have moved 20km and the van would have moved 80km.

The distance between them was 300km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

300km-(20km+80km) = 200km

So now the distance between them is 200km.

Now another hour passes. The distance between them was 200km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

200km-(20km+80km) = 100km

So now the distance between them is 100km

Now another hour passes. The distance between them was 100km. But the bike moved 20km and the van moved 80km, since its been one hour. Which means the distance between them is less.

100km-(20km+80km) = 0km

So now the distance between them is 0km, which means they have met. If we count, it took them 3 hours.

:

Step 1)

Add both speeds. 20km+80km=100km

Step 2)

Total distance between them = 300km

So do 300km/100km = 3hours.

______

The solution is: .

————

Hope this helped!

4 0
3 years ago
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