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LUCKY_DIMON [66]
3 years ago
14

Definitions

Physics
1 answer:
Goryan [66]3 years ago
4 0

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A reference frame can be moving. To make sure that newtons laws still apply, the reference frame must not be accelerating.
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Vector A has magnitude 8.00 mm and is in the xy-plane at an angle of 127∘ counterclockwise from the +x–axis (37∘ past the +y-axi
Ilia_Sergeevich [38]

Answer:

-75.35°

Explanation:

Let C be the sum of the two vectors A and B. Hence, we can write the following  

A_{x} +B_{x} =C_{x} ......(1)\\A_{y} +B_{y} =C_{y} ......(2)

but since the vector C is in the -y direction, C_{x}  = 0 and C_{y} = —12 m.  

Thus  

B_{x} =-A_{x} =-[-Acos(180-127)]=(8)*cos(53)\\B_{x} =4.81m

similarly, we can determine B_{y} by rearranging equation (1)  

 B_{y} =C_{y} -A_{y} =-12m-[(8)*sin(53)\\B_{y} =-18.4m

so the magnitude of B is

B=\sqrt{B_{x}^2+B_{y}^2  } \\B=19m

Finally, the direction of B can be calculated as follows  

Ф=tan^{-1} (\frac{B_{y} }{B_{x} } )\\=-75.35

hence the vector B makes an angle of 75.35 clockwise with + x axis

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A toy car is moving horizontally and started its motion from a position of X1 = 2 cm, then after 3 seconds it reached at a posit
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Since distance is a scalar and not a vector, the total distance traveled is the sum of all the distances covered throughout the journey.

In Physics, we have two categories of quantities;

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The difference between vectors and scalars is that vectors has direction but scalars do not have direction. Both quantities posses magnitude.

The total distance covered can be obtained algebraically since distance is a scalar.

Hence, total distance covered = 2 cm + 6cm + 5 cm = 13 cm

Learn more: brainly.com/question/14093917

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