The potential difference between the plates will be 1552 Volts.
<h3>What is a potential difference?</h3>
Voltage, or the difference in electric potential between two points, is defined as the amount of labor per unit of charge needed to move a test charge between the two points.
Given that a 3.7-f capacitor that stores sufficient energy to operate a 75.0-w
The potential difference will be calculated by the formula below:-
Q = I t
Where I = charge / time
Q = V * C
V C = I t
V = I t / C
V = 75 C/s x 60 sec / 2.9 faraday
V = 1552 Volts
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Answer:
r2 = 2.401557 cm
distance = 0.10 cm
Explanation:
given data
radius = 2.50 cm
density = 15.0 nC/m
voltmeter read = 175
solution
we know here potential difference that is express as
ΔV = 
...........1
so here
as here 
is linear charge density
r2 = r1 × 
r2 = 2.40 × 
r2 = 2.401557 cm
and
here distance above surface will be
distance = r1 - r2
distance = 2.50 - 2.40
distance = 0.10 cm
It carry its loads from the sand and outher partials in it
1, 2 & 4 are going to be the the correct answer for the question
Answer: Option (A) is the correct answer.
Explanation:
When more and more energy is provided to a gas then its atoms move more rapidly.
This rapid and continuous movement converts the gas into hot ionized ions which have positively charged ions and negatively charged electrons.
Therefore, we can conclude that as the atoms move faster, the gas can change into a plasma.
