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2 years ago

Is a frame of reference usually moving

1 answer:

5 0

A reference frame can be moving. To make sure that newtons laws still apply, the reference frame must not be accelerating.

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A sinusoidally oscillating current I ( t ) with an amplitude of 9.55 A and a frequency of 359 cycles per second is carried by a

UNO [17]

Answer:

$P_{avg} = 6.283*10^{-9} \ W$

Explanation:

Given that;

I₀ = 9.55 A

f = 359 cycles/s

b = 72.2 cm

c = 32.5 cm

a = 80.2 cm

Using the formula;

$\phi = \frac{\mu_o Ic }{2 \pi} In (\frac{b+a}{b})$

where;

$E= \frac{d \phi}{dt}$

$E = \frac{\mu_o}{2 \pi}c In (\frac{b+a}{a}) I_o \omega cos \omega t$

$E_{rms} = \frac { {\frac{\mu_o \ c}{2 \pi} In (\frac{b+a}{a}) I_o (2 \pi f)}}{\sqrt{2}}$

Replacing our values into above equation; we have:

$E_{rms} = \frac { {\frac{4 \pi*10^{-7}*0.325}{2 \pi} In (\frac{72.2+80.2}{80.2}) *9.55 (2 \pi *359)}}{\sqrt{2}}$

$E_{rms} = \frac {8.98909588*10^{-4} }{\sqrt{2}}$

$E_{rms} = 6.356*10^{-4} \ V$

Then the $P_{avg$ is calculated as:

$P_{avg} = \frac{E^2}{R}$

$P_{avg} = \frac{(6.356*10^{-4})^2}{64.3}$

$P_{avg} = 6.283*10^{-9} \ W$

6 0

3 years ago

A car has two horns, one emitting a frequency of 199 hz and the other emitting a frequency of 203 hz. what beat frequency do the

andriy [413]

Beat frequency, fb = |f2-f1|

That is, beat frequency is the absolute difference between two frequencies. Is is as a results of destructive and constructive inferences.

Therefore, in this case:

fb = 203 - 199 = 4 Hz

3 0

2 years ago

Electromagnetic waves can travel through a vacuum. true or false

torisob [31]

Answer:

false

Explanation:

5 0

2 years ago

Read 2 more answers

As seen, any object with electric charge, stationary or moving, other than the charged object that created the field, experience

sammy [17]

Answer:

The answer and explanation is in the attached file

6 0

3 years ago

A skateboarder is moving at 2.00m/s and increases his velcity at a rate of 1.6m/s/s for 6.0 seconds. What is the displacement of

MrRissso [65]

Answer:

S = 40.8m

Explanation:

Given the following data;

Initial velocity, u = 2m/s

Acceleration, a = 1.6m/s²

Time, t = 6secs

Required to find the displacement

Displacement, S = ?

The displacement of an object is given by the second equation of motion;

$S = ut + \frac {1}{2}at^{2}$

Where;

S represents the displacement measured in meters.

u represents the initial velocity measured in meters per seconds.

t represents the time measured in seconds.

a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

$S = 2*6 + \frac {1}{2}*(1.6)*6^{2}$

$S = 12 + 0.8*36$

$S = 12 + 28.8$

S = 40.8m

Therefore, the displacement of the skateboarder during this game is 40.8 meters.

7 0

2 years ago