The interatomic spring stiffness for tungsten is determined from Young's modulus measurements to be 90 N/m. The mass of one mole
of tungsten is 0.185 kg. If we model a block of tungsten as a collection of atomic "oscillators" (masses on springs), what is one quantum of energy for one of these atomic oscillators? Note that since each oscillator is attached to two "springs", and each "spring" is half the length of the interatomic bond, the effective interatomic spring stiffness for one of these oscillators is 4 times the calculated value given above. Use these precise values for the constants: ℏ = 1.0546 10-34 J · s (Planck's constant divided by 2π) Avogadro's number = 6.0221 1023 molecules/mole kB = 1.3807 10-23 J/K (the Boltzmann constant)
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Answer:
The person can jump 48 m on the Moon
Explanation:
The question parameters are;
The maximum long jump distance of a person on Earth, = 3 m
The acceleration due to gravity on the Moon = 1 ÷ 16 of that on Earth
The distance the person can jump on the Moon is given as follows;
A person performing a jump across an horizontal distance on Earth (under gravitational force) follows the path of the motion of a projectile
The horizontal range, , of a projectile motion is found by using the following formula
Where;
g = The acceleration due to gravity = 9.8 m/s²
Therefore, we have;
u² = 3 m × 9.8 m/s² = 29.4 m²/s²
Therefore, on the Moon, we have;
The acceleration due to gravity on the Moon, = 1/16 × g
∴ = 1/16 × g = 1/16 × 9.8 m/s² ≈ 0.6125 m/s²
The maximum distance the person can jump on the Moon with the same velocity which was used on Earth is ≈ 48 m