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musickatia [10]
3 years ago
15

The interatomic spring stiffness for tungsten is determined from Young's modulus measurements to be 90 N/m. The mass of one mole

of tungsten is 0.185 kg. If we model a block of tungsten as a collection of atomic "oscillators" (masses on springs), what is one quantum of energy for one of these atomic oscillators? Note that since each oscillator is attached to two "springs", and each "spring" is half the length of the interatomic bond, the effective interatomic spring stiffness for one of these oscillators is 4 times the calculated value given above. Use these precise values for the constants: ℏ = 1.0546 10-34 J · s (Planck's constant divided by 2π) Avogadro's number = 6.0221 1023 molecules/mole kB = 1.3807 10-23 J/K (the Boltzmann constant)

Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer:

Explanation:

solution below

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Figure 1.18 (Chapter 1) shows the Hoover Dam Bridge over
stiks02 [169]

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Explanation:

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y=y_{o}+V_{o} t+\frac{gt^{2}}{2}  

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y= 0m is the final height of the object (when it makes splash)

y_{o}=271 m  is the initial height of the object

V_{o}=0 m/s  is the initial velocity of the object (it was dropped)

g=-9.8m/s^{2}  is the acceleration due gravity (directed downwards)

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0=y_{o}+0+\frac{gt^{2}}{2}  

Clearing t:

t=\sqrt{\frac{-2y_{o}}{g}}  

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6 0
4 years ago
Mike has a mass of 97 kg. He jumps out of a perfectly good airplane that is 2000 m above the ground. After he falls 1000 m, when
Ne4ueva [31]

Answer:

a)  fr = 224.3 N , b)   fr = 224.3 N , c)   v = 198.0  m/s

Explanation:

a) For this exercise let's start by calculating the acceleration in the fall

             v² = v₀² - 2 a (y-y₀)

When it jumps the initial vertical speed is zero

             a = -v² / 2 (y-y₀)

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             a = 2,312 m / s²

Let's use the second net law to enter the average friction force

            fr = m a

            fr = 97 2,312

            fr = 224.3 N

b) let's look for acceleration

            v² = v₀² - 2 a y

            a = (v² –v₀²) / 2 (y-y₀)

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            fr = m a

            fr = 97 2,304

            fr = 223.5 N

c) the speed of the wallet is searched with kinematics

           v² = v₀² - 2 g (y-y₀)

           v = √ (0-2 9.8 (0-2000))

           v = 198.0  m/s

4 0
3 years ago
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