1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Naddika [18.5K]
3 years ago
7

A pump lifts 260 kg of water per hour a height of 3.5 m . What is the minimum necessary power output rating of the water pump in

watts? Express your answer using two significant figures.
Physics
1 answer:
Phantasy [73]3 years ago
7 0

Answer:

2.5 Watts.

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 260 Kg

Time (t) = 1 h

Height (g) = 3.5 m

Power (P) =.?

Next, we shall determine the energy. This can be obtained as follow:

Mass (m) = 260 Kg

Height (g) = 3.5 m

Acceleration due to gravity (g) = 10 m/s²

Energy (E) =?

E = mgh

E = 260 × 10 × 3.5

E = 9100 J

Finally, we shall determine the power. This can be obtained as follow:

Time (t) = 1 h = 3600 s

Energy (E) = 9100 J

Power (P) =.?

P = E/t

P = 9100 / 3600

P = 2.5 Watts

Thus, the power is 2.5 Watts.

You might be interested in
A certain car traveling at 97 km/h can stop in 47 m on a level road find the coefficient of friction
IrinaVladis [17]

The coefficient of friction between the road and the car's tire is determined as 0.78.

<h3>Acceleration of the car</h3>

The acceleration of the car is calculated as follows;

v² = u² - 2as

0 = u² - 2as

a = u²/2s

where;

  • u is the initial velocity = 97 km/h = 26.94 m/s

a = (26.94)²/(2 x 47)

a = 7.72 m/s²

<h3>Coefficient of friction</h3>

μ = a/g

μ = (7.72)/9.8

μ = 0.78

Learn more about coefficient of friction here: brainly.com/question/14121363

#SPJ1

5 0
2 years ago
ASAP
iris [78.8K]

Answer:

A) Energy is dissipated into heat and sound energy due to Friction

B) The energy goes into heat and sound energy due to friction again, otherwise the cart would accelerate due to an unbalanced force. Therefore, we know there's friction, and the friction causes energy loss.

5 0
3 years ago
Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars
zhuklara [117]

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

T^2 \propto R^3

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

T^2 \propto R^3

T^2 = kR^3

Substituting the values, we get the value of constant k for mars.

687^2 = k\times (2.279 \times 10^{11})^3

k = 3.92 \times 10^{-29}

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

365^3 = 3.92\times 10^{-29} R^3

R^3 = 3.39 \times 10^{33}

R= 1.50 \times 10^{11}\;\rm m

Hence we can conclude that the distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

To know more about Kepler's third law, follow the link given below.

brainly.com/question/7783290.

6 0
3 years ago
By what factor will the acceleration of an object change its mass stays constant but the force acting on it triples
Viktor [21]

Answer:

lacceleration is given by

a=F/m

With force acting on the object remained constant ,the acceleration is inversly proportional to mass of the object i.e with increase in mass =>acceleration decreases and with decrease in mass => acceleration increases.

a)

acceleration decreases

b)

acceleration increase

7 0
3 years ago
A machine accelerates a 5 kg missile from rest to a speed of 5 km/s. The net force accelerating the missile 500,000 N. How long
Gnoma [55]
Final velocity = 5km/sec = 5000 m/sec
Initial velocity = 0, mass = 5kg and force = 500,000 N
F = m(Vf-Vi)/time
Time = m(Vf-Vi)/force = 5*5000/500000 = 0.05 seconds
So, it takes 0.05 sec to arrive at the speed of 5km/s.
3 0
3 years ago
Other questions:
  • A car in front of the school goes from rest to 5.6 m/s in 3 seconds. What is its acceleration?
    12·1 answer
  • What are the uses of oxygen?
    7·2 answers
  • How does the gravity in the space shuttle compare with the gravity on earth’s surface?
    6·2 answers
  • Please help ASAP! Due in 10 minutes. Will give Brainliest.
    12·1 answer
  • Two capacitors are identical, except that one is empty and theother is filled with a dielectric (κ = 3.60). The empty capacitor
    5·1 answer
  • If an piano and an apple are dropped in a tunnel without air.which would hit the ground first
    12·1 answer
  • the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equ
    8·1 answer
  • A satellite with mass 6000 kg is orbiting the planet at 2500 km above the planet's
    8·1 answer
  • If you blow across the open end of a soda bottle and produce a tone of 250 Hz, what will be the frequency of the next harmonic h
    15·1 answer
  • What is volt?<br><img src="https://tex.z-dn.net/?f=%20%5C%5C%20" id="TexFormula1" title=" \\ " alt=" \\ " align="absmiddle" clas
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!