4m- t = m for m.......................................

Mazyrski [523]

Answer: Q=1/2p+15,= p=2q-30= Slope = 1.000/2.000 = 0.500

p-intercept = -30/1 = -30.00000

q-intercept = 30/2 = 15

Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

p-(2*q-30)=0

Solve p-2q+30 = 0

we have an equation of a straight line. Such an equation is usually written y=mx+b ("y=mx+c" in the UK).

"y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.

In this formula :

y tells us how far up the line goes

x tells us how far along

m is the Slope or Gradient i.e. how steep the line is

b is the Y-intercept i.e. where the line crosses the Y axis

The X and Y intercepts and the Slope are called the line properties. We shall now graph the line p-2q+30 = 0 and calculate its properties

Notice that when p = 0 the value of q is 15/1 so this line "cuts" the q axis at q=15.00000

q-intercept = 30/2 = 15

When q = 0 the value of p is -30/1 Our line therefore "cuts" the p axis at p=-30.00000

p-intercept = -30/1 = -30.00000

Slope is defined as the change in q divided by the change in p. We note that for p=0, the value of q is 15.000 and for p=2.000, the value of q is 16.000. So, for a change of 2.000 in p (The change in p is sometimes referred to as "RUN") we get a change of 16.000 - 15.000 = 1.000 in q. (The change in q is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

Slope = 1.000/2.000 = 0.500

7 0

3 years ago

Me ajuda ai por favor tenho que entregar amanhã

elena-14-01-66 [18.8K]

a) (2a - b)² = (4a² - 4ab + b²)

b) (10m - n²)² = (100m² - 20mn² + n⁴)

c) (4x - 4²) = (16x² - 8x + 4⁴)

d) ${( \frac{1}{3} x - y) }^{2} = ({ \frac{1}{9}x }^{2} - \frac{2}{3} xy + {y}^{2} )$

e)

$(0.25 - a) ^{2} = (0.25^{2} - (2)(0.25)a + {a}^{2} ) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = ( \frac{1}{16} - \frac{1}{2} a + {a}^{2} )$