Explanation:
There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.
<u>Statement</u> . . . . <u>Reason</u>
2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle
3. AD ≅ BD
and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle
4. ∠CAE = ∠CAD +∠DAE
and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate
5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality
6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality
7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality
8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate
9. ∠ACD ≅ ∠BCD . . . . CPCTC
10. DC bisects ∠ACB . . . . definition of angle bisector
Answer:
2^3×6-5÷3-3×4^-4 solving 8×1÷0×0=8÷0= 8
Answer:
12 in
Step-by-step explanation:
sin(28°)=
a=sin(28°)*25
=11.7367
≈12
9514 1404 393
Answer:
Step-by-step explanation:
A) If the playing times are to be the same, then the two expressions for playing time will be equal to each other.
Ron = Sam
3 +1.25c = 8 +0.75c
0.50c +3 = 8 . . . . . . . . . . subtract 0.75c from both sides
0.50c = 5 . . . . . . . . . . . subtract 3 from both sides
c = 5/0.50 = 10 . . . . . divide by the coefficient of c
Each would have to complete 10 chores for their playing times to be the same.
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B) When c = 4, we have ...
Ron: 3 +1.25·4 = 3 +5 = 8
Sam: 8 +0.75·4 = 8 +3 = 11
Sam spent the most gaming time if both completed 4 chores.
Answer:
24 units²
Step-by-step explanation: