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Fofino [41]
3 years ago
9

"Two waves of the same frequency have amplitudes 1.00 and 2.00. They interfere at a point where their phase difference is 60.0°.

What is the resultant amplitude?"
Physics
1 answer:
vesna_86 [32]3 years ago
6 0

Answer:

The resultant amplitude of the two waves is 2.65.

Explanation:

Given;

amplitude of the first wave, A₁ = 1

amplitude of the second wave, A₂ = 2

phase difference of the two amplitudes, θ = 60.0°.

The resultant amplitude of two waves after interference is given by;

A = \sqrt{A_1^2 + A_2^2 + 2A_1A_2Cos \theta} \\\\A = \sqrt{1^2 + 2^2 + 2(1)(2)Cos 60} \\\\A= 2.65

Therefore, the resultant amplitude of the two waves is 2.65.

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3 years ago
In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the met
qwelly [4]

Answer:

B. The number of electrons emitted from the metal per second increases.

Explanation:

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2 years ago
Simple physics question, check the document. Should take about 3-5 minutes.
Ahat [919]

Answer:

The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N

Explanation:

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Net force on 4.3 kg block is: 63 N - R21

Forces on the 6.3 kg block are:

R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.

So net force on the 6.3 kg block is: R12 - 11 N

According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").

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Answer:

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temperature drops from 17 to -52*C

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