Question

"Two waves of the same frequency have amplitudes 1.00 and 2.00. They interfere at a point where their phase difference is 60.0°. What is the resultant amplitude?"

Answer 1

Answer:

The resultant amplitude of the two waves is 2.65.

Explanation:

Given;

amplitude of the first wave, A₁ = 1

amplitude of the second wave, A₂ = 2

phase difference of the two amplitudes, θ = 60.0°.

The resultant amplitude of two waves after interference is given by;

$A = \sqrt{A_1^2 + A_2^2 + 2A_1A_2Cos \theta} \\\\A = \sqrt{1^2 + 2^2 + 2(1)(2)Cos 60} \\\\A= 2.65$

Therefore, the resultant amplitude of the two waves is 2.65.