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3 years ago

I need this fast can you help me o give 12 points

Physics

2 answers:

Elanso [62]3 years ago

7 0

Water as it's the highest specific heat capacity
Hope this helps x

vodomira [7]3 years ago

5 0

Brick is the correct answer

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1.A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upwar

Charra [1.4K]

Answer:

1. t = 3.27 seconds

2. y = 147.3 m

Explanation:

Newton's Laws of Motions.

y = v₁t + 1/2 at²

a = (v₂-v₁)/t

where

y = the vertical distance travelled

v₁ = the initial velocity

v₂ = the final velocity

t = the time

a = the acceleration

final velocity is equal to 0.

So, v₂ = 0.

a = (v₂-v₁)/t

a = (0-30)/t

a = -30/t

plugin values into the first equation:

y = v₁t + 1/2 at²

49 = 30t + 1/2 (-30/t)t²

49 = 30t -15t

49 = 15 t

t = 49/15

t = 3.27 seconds

y = v₁t + 1/2 at²

a = -30/3.27

a = 9.2

y = 30(3.27) + 1/2(9.2) 3.27²

y = 147.3 m

6 0

4 years ago

Cuales son dispositivos de salida?

Jobisdone [24]

Answer:

el monitor,las impresoras y las memorias portátiles

5 0

3 years ago

What is one advantage of using a computer over a graphing calculator?

Dahasolnce [82]

A computer can show you how it is done and how they got to that solution while a graphing calculator can only show you the solution.

4 0

3 years ago

Read 2 more answers

Alex, parked by the side of an east-west road, is watching car P, which is moving in a westerly direction. Barbara, driving east

Alexxandr [17]

Answer:

$v_{PB} = 130\ km/h$

Explanation:

Since, Alex is at rest. Therefore, the speed measured by him will be the absolute speed of car P. Therefore, taking easterly direction as positive:

$Absolute\ Velocity\ of\ Car\ P = v_{P} = -78\ km/h$

And the absolute velocity of Barbara's Car is given as: $Absolute\ Velocity\ of\ Barbara's\ Car = v_{B} = 52\ km/h$

Now, for the velocity of Car p with respect to the velocity of Barbara's Car can be given s follows:

$Velocity\ of\ Car\ P\ measured\ by\ Barbara = v_{PB} = v_{B}-v_{P}\\\\v_{PB} = 52\ km/h-(-78\ km/h)$

$v_{PB} = 130\ km/h$

6 0

3 years ago

A truck traveling at a constant speed of 28 m/s passes a more slowly moving car. The instant the truck passes the car, the car b

choli [55]

Answer:

the velocity of car when it passes the truck is u = 16.33 m/s

Explanation:

given,

constant speed of truck = 28 m/s

acceleration of car = 1.2 m/s²

passes the truck in 545 m

speed of the car when it just pass the truck = ?

time taken by the truck to travel 545 m

time = $\dfrac{distance}{speed}$

time = $\dfrac{545}{28}$

time =19.46 s

velocity of the car when it crosses the truck

$S = ut + \dfrac{1}{2}at^2$

$545= u\times 19.46 + \dfrac{1}{2} \times 1.2 \times 19.46^2$

u = 16.33 m/s

the velocity of car when it passes the truck is u = 16.33 m/s

5 0

4 years ago