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1 year ago

The potential at point P is the work required to bring a one-coulomb test charge from far

Physics

1 answer:

MatroZZZ [7]1 year ago

7 0

True so true Its so true

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Orlov [11]

Answer:

I dont know this but I have an app for you if your really strangling

Explanation:

its called Qanda. it really good and teachers help you a lot

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3 years ago

Help when u can! I feel like it's C, but I just want to make sure before I submit the test.

Marat540 [252]

(D)

Explanation:

This kind of bond where the electrons are transferred is called ionic bond. This bond occurs between a metallic and non-metallic elements. The other kind of bond (covalent) involves the sharing of electrons and this happens between non-metallic elements.

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2 years ago

a bullet with a mass of 4.0g and a speed of 650m/s is fired at a block of wood with a mass of 0.095kg. the block rests on a fric

n200080 [17]

Part a)

Here in this we can use momentum conservation as there is no external force on it

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} +m_2v_{2f}$

here we know that

$m_1 = 0.004 kg$

$v_{1i} = 650 m/s$

$m_2 = 0.095$

$v_{2i} = 0$

$v_{2f} = 23 m/s$

now by above equation

$0.004*650 + 0.095* 0 = 0.004*v + 0.095*23$

$2.6 + 0 = 0.004*v + 2.185$

$v = 103.75 m/s$

Part b)

Final kinetic energy of the system

$KE_f = \frac{1}{2}m_1v_{1f}^2 + \frac{1}{2}m_2v_{2f}^2$

$KE_f = \frac{1}{2}*0.004*(103.75^2) + \frac{1}{2}*(0.095)*23^2$

$KE_f = 46.65 J$

Initial Kinetic energy of the system will be

$KE_f = \frac{1}{2}m_1v_{1i}^2 + \frac{1}{2}m_2v_{2i}^2$

$KE_f = \frac{1}{2}*0.004*(650^2) + \frac{1}{2}*(0.095)*0^2$

$KE_f = 845 J$

So here kinetic energy is decreased for this system

final energy is less than initial energy

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2 years ago

Which element would have the lowest electronegativity? (1 point)O an element with a large number of valence electrons and a larg

nekit [7.7K]

Answer:

an electron with element with large number of valence electron and large atomic <u>radius</u>

8 0

2 years ago

What does it mean when the mark on the ramrod disappears into the barrel of the muzzleloader?

bagirrra123 [75]

The firearm is unloaded.

The ramrod establishes whether the firearm is loaded or unloaded. It thrusts the bullet down the barrel. It is marked by wrapping some tape around it ( at the muzzle end ). This is to effectively signal if the muzzleloader is empty or loaded.

8 0

3 years ago