The time taken by the pulse to travel from one support to the other is 0.208 s.
<h3>Given:</h3>The mass of the cord is m = 0.65 kg.
The distance between the supports is, d = 8.0 m.
The tension in the cord is T = 120 N.
The time taken by the pulse to travel from one support to the other is given as,
Here, v is the linear velocity of a pulse. Its value is,
Then,
Thus, the time taken by the pulse to travel from one support to the other is 0.208 s.
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Answer:
A charge of -5.02 nC is uniformly distributed on a thin square sheet of nonconducting material of edge length 21.8 cm. "What is the surface charge density of the sheet"?
Explanation:
Surface charge density is a measure of how much electric charge is accumulated over a surface. It can be calculated as the charge per unit area.
We will convert all parameters in SI units.
Charge = Q = -5.02nC
Q = -5.02×C
As it is clear from question that Sheet is a square (All sides will be of equal length)
Area = A = (21.8×m) (21.8×
m) = 4.75×
m²
A = 4.75×m²
Surface charge density = Q/A
Surface charge density = (-5.02×C)/(4.75×
m²)
Surface charge density = -1.057× C
The work done on the sail is 600 J
Explanation:
The work done to lift the sail is equal to the gain in gravitational potential energy of the sail, therefore is:
where
m is the mass of the sail
g is the acceleration of gravity
(mg) is the weight of the sail
is the change in height of the sail
In this problem we have
mg = 150 N (weight)
Substituting, we find the work done:
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