Answer:
Option C. 20 V
Explanation:
We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:
Resistor 1 (R₁) = 20 Ω
Resistor 2 (R₂) = 40 Ω
Resistor 3 (R₃) = 60 Ω
Equivalent Resistance (R) =?
R = R₁ + R₂ + R₃ (series arrangement)
R = 20 + 40 + 60
R = 120 Ω
Next, we shall determine the current in the circuit. This can be obtained as follow:
Voltage (V) = 60 V
Equivalent Resistance (R) = 120 Ω
Current (I) =?
V = IR
60 = I × 120
Divide both side by 120
I = 60 / 120
I = 0.5 A
Finally, we shall determine the potential drop across R₂. This can be obtained as follow:
Current (I) = 0.5 A
Resistor 2 (R₂) = 40 Ω
Voltage (V) =?
V = IR₂
V = 0.5 × 40
V = 20 V
Therefore, the potential drop across R₂ is 20 V
Explanation:
The concentration of salt after t minutes is given by :
A tank contains 9000 L of pure water. Brine that contains 40 g of salt per liter of water is pumped into the tank at a rate of 25 L/min.
We need to find the concentration approach at
So,
Put
Since,
C(t) = 40 g/L
So, at the concentration approaches to 40 g/L. Hence, this is the required solution.
Id say d because it releases hydrogen and on the other hand a base receives it
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Answer:The gravitational force on the ball due to earth is exactly the same as the gravitational force on earth due to the ball
Explanation:
The gravitational force exist in pair. It form action-reaction pair.
'H' = height at any time
'T' = time after both actions
'G' = acceleration of gravity
'S' = speed at the beginning of time
Let's call 'up' the positive direction.
Let's assume that the tossed stone is tossed from the ground, not from the tower.
For the stone dropped from the 50m tower:
H = +50 - (1/2) G T²
For the stone tossed upward from the ground:
H = +20T - (1/2) G T²
When the stones' paths cross, their <em>H</em>eights are equal.
50 - (1/2) G T² = 20T - (1/2) G T²
Wow ! Look at that ! Add (1/2) G T² to each side of that equation,
and all we have left is:
50 = 20T Isn't that incredible ? ! ?
Divide each side by 20 :
<u>2.5 = T</u>
The stones meet in the air 2.5 seconds after the drop/toss.
I want to see something:
What is their height, and what is the tossed stone doing, when they meet ?
Their height is +50 - (1/2) G T² = 19.375 meters
The speed of the tossed stone is +20 - (1/2) G T = +7.75 m/s ... still moving up.
I wanted to see whether the tossed stone had reached the peak of the toss,
and was falling when the dropped stone overtook it. The answer is no ... the
dropped stone was still moving up at 7.75 m/s when it met the dropped one.