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yKpoI14uk [10]
3 years ago
7

Assuming constant velocities, if a fastball pitch is thrown and travels at 40 m/s toward home plate, 18 m away, and the head of

the bat is simultaneously traveling toward the ball at 18.0 m/s, how much time elapses before the bat hits the ball?a. About 0.3 sb. About 0.6 sc. About 0.9 sd. About 1.2 s
Physics
1 answer:
PolarNik [594]3 years ago
8 0
<h2>Option A is the correct answer.</h2>

Explanation:

Here velocity of ball and bat are in opposite direction.

Velocity of ball = 40 m/s

Velocity of bat = 18 m/s

Since they are in opposite direction relative velocity is given by,

           Relative velocity = 40 + 18 = 58 m/s

Distance to home plate = 18 m

We have

                Displacement = Velocity x Time

                           18 = 58 x Time

                          Time = 0.3 seconds

Option A is the correct answer.

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Which statement best describes the relationship between mass and gravitational attraction (pull)?
Gnesinka [82]

Answer:

The first option, "The more mass an object has, the greater the gravitational pull. "

Explanation:

Newton's Law of Gravity states that F_G=\frac{Gm_1m_2}{r^{2}}, where G is the gravitational constant, m_1 and m_2 are the masses of the two objects, and <em>r</em> is the distance between the objects' centers. Because the objects' masses are in the fraction's numerator, they are directly proportional to F_G, and increasing the mass of one or both objects increases the gravitational pull.

Please have a great day! I hope this helps you understand the question!

7 0
3 years ago
When a 440-Hz tuning fork and a piano key are struck together, five beats are heard. If the pitch of the note on the piano is lo
vovangra [49]
The frequency would also be lower
7 0
4 years ago
Read 2 more answers
Every thing is in the picture
vekshin1

Answer:

156

Explanation:

74+82=156

5 0
3 years ago
In a double-slit experiment, it is observed that the distance between adjacent maxima on a remote screen is 1.0 cm. What happens
kobusy [5.1K]

Answer:

C) It increases to 2.0 cm

Explanation:

In a double-slit diffraction experiment, the distance on the screen between two adjacent maxima is given by

\Delta y = \frac{\lambda D}{d}

where

\lambda is the wavelength of the wave

D is the distance of the screen from the slits

d is the separation between the slits

In this problem, the initial distance between adjacent maxima is 1.0 cm. Later, the slit separation is cut in a half, which means that the new slit separation is

d'=\frac{d}{2}

Substituting into the equation, we find that the new separation between the maxima is

\Delta y' = \frac{\lambda D}{d/2}=2(\frac{\lambda D}{d})=2\Delta y

So, the distance increases by a factor 2: therefore, the new separation between the maxima will be 2.0 cm.

5 0
3 years ago
A spring that has a spring constant of 440 N/m exerts a force of 88 N on a box. What is the displacement of the spring? 0. 2 m 5
mina [271]

The displacement of a spring is directly proportional to the applied force. The displacement of the given spring is 50.45 m.

<h2></h2><h2>From Hooke's law:</h2>

F = kx

Where,

F - force applied = 88 N

k - spring constant = 440 N/m

x - displacement = ?

Put the values in the formula,

88  = 440 \times x\\\\x = \dfrac {440 }{88}\\\\x = 50.45 \rm \ m

Therefore, the displacement of the given spring is 50.45 m.

Learn more about Hooke's law:

brainly.com/question/3355345

6 0
2 years ago
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