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lina2011 [118]
3 years ago
12

Light of wavelength 550 nm comes into a thin slit and produces a diffraction pattern on a board 8.0 m away. The first minimum da

rk fringe appears 3 mm from the central maximum. What is the width of the slit?
Physics
1 answer:
FrozenT [24]3 years ago
5 0

Answer:

Width of the slit will be equal to 1.47 mm

Explanation:

We have given wavelength of the light \lambda =550nm=550\times 10^{-9}m

Distance D = 8 m

Distance between first minimum dark fringe and the central maximum is 2 mm

So x=3\times 10^{-3}m

We have to find the width of the slit

For the first order wavelength is equal to \lambda =\frac{x}{D}\times a, here a width of slit

So a=\frac{\lambda D}{x}=\frac{550\times 10^{-9}\times 8}{3\times 10^{-3}}=1466.666\times 10^{-6}=1.47mm

So width of the slit will be equal to 1.47 mm

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