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3 years ago

The cost of a long-distance telephone call is given by the function

1 answer:

3 0

The slope would represent the cost per minute, since m is the length of the call in minutes. Logically, D) Cost per minute, is the only one that would work. The connection cost would be just added in, and you wouldn't multiply the cost of having a phone line by how many minutes you're on the phone. The length of the call is already there, it's m, so that wouldn't work either. Therefore, D, cost per minute, is the logical answer. The slope in the equation represents D, cost per minute.

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A ball is launched from a 682.276 meter tall platform. the equation for the ball's height h at time t seconds after launch is h(

blagie [28]

The maximum height the ball achieves before landing is 682.276 meters at t = 0.

<h3>What are maxima and minima?</h3>

Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.

We have a function:

h(t) = -4.9t² + 682.276

Which represents the ball's height h at time t seconds.

To find the maximum height first find the first derivative of the function and equate it to zero

h'(t) = -9.8t = 0

t = 0

Find second derivative:

h''(t) = -9.8

At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.

Maximum height at t = 0:

h(0) = 682.276 meters

Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.

Learn more about the maxima and minima here:

brainly.com/question/6422517

#SPJ1

4 0

2 years ago

Someone helppppp!!!!!!

ioda

lol omg I don’t know

6 0

3 years ago

Read 2 more answers

A cherry falls from a tree branch that is 9 feet above the ground.

miss Akunina [59]

The cinematic equation is:
h (t) = (1/2) * a * t ^ 2 + vo * t + h0
Where,
a: acceleration
vo: initial speed
h0: initial height
Substituting values:
h (t) = (1/2) * (- 32) * t ^ 2 + (0) * t + 9
h (t) = - 16t ^ 2 + 9
For t = 0.2 we have:
h (0.2) = - 16 * (0.2) ^ 2 + 9
h (0.2) = 8.36 feet
To touch the ground we have:
-16t ^ 2 + 9 = 0
16t ^ 2 = 9
t = root (9/16)
t = 0.75 s
Answer:
The height of the cherry after 0.2 seconds is:
h (0.2) = 8.36 feet
the cherry hits the ground at:
t = 0.75 s

5 0

3 years ago

What is the height of an equilateral triangle if the sides are 10

4vir4ik [10]

Answer:

The height of the equilateral triangle is $5\sqrt{3}\ units$

Step-by-step explanation:

we know that

An equilateral triangle has three congruent sides, and three congruent angles that each measure 60 degrees

To find out the height of an equilateral triangle, apply the Pythagoras Theorem in the right triangle ABD

Remember that the height of an equilateral triangle bisects the base.

see the attached figure to better understand the problem

$AB^2=AD^2+BD^2$

substitute the given values

$10^2=5^2+BD^2$

Solve for BD

$100=25+BD^2$

$BD^2=100-25$

$BD^2=75$

$BD=\sqrt{75}\ units$

simplify

$BD=5\sqrt{3}\ units$ `

therefore

The height of the equilateral triangle is $5\sqrt{3}\ units$

7 0

4 years ago

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu

V125BC [204]

Answer:

$\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1\times ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^{12}C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$

$=\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Which is the required expression.

3 0

3 years ago

Read 2 more answers