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8_murik_8 [283]
3 years ago
10

PLEASEEEE HELPPPPAdd. 3+(-7)=​

Mathematics
2 answers:
Leona [35]3 years ago
6 0

Answer:

-4

Step-by-step explanation:

Remove Parentheses

3-7

Subtract

3-7 = -4

Answer

-4

Hope this helped

Brainliest is appreciated/

kow [346]3 years ago
4 0

Answer:

Step-by-step explanation:

It’s exactly like saying -7 + 3.. -7 is the bigger number so you take away from that the answer is -4

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sattari [20]
I’m pretty sure that it’s the third answer (q^12)! :)
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2 years ago
18 minus 7 x = negative 20.5 What is the value of x? Negative 5 and one-half Negative StartFraction 5 Over 14 EndFraction StartF
alisha [4.7K]

Answer:

x = 5.5  (Fraction 5 and one-half)

Step-by-step explanation:

18 - 7x = -20.5

-18            -18

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3 years ago
Which equation is the inverse of y = 2x^2 - 8?
evablogger [386]

Answer: A

Step-by-step explanation:

y=2x^2-8

1. Swap x and y.

x=2y^2-8

2. Solve for the new y.

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x+8=2y^2

Divide by 2.

\frac{x+8}{2}=y^2

Extract the square root.

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6 0
3 years ago
What number must you add to complete the square?<br> x^2 + 2x = -1
Andru [333]
\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}


If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248


\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}

6 0
3 years ago
Read 2 more answers
Condensing Logarithmic Expression In Exercise,use the properties of logarithms to rewrite the expression as the logarithm of a s
nevsk [136]

Answer:

[ln \frac{x(x^2 + 1)}{(x + 1)}]^\frac{3}{2}

Step-by-step explanation:

\frac{3}{2} [ln x(x^2 + 1) - ln(x + 1)]

ln(m/n)= lnm - ln(n)

\frac{3}{2}[ln x(x^2 + 1) - ln(x + 1)]

\frac{3}{2}[ln \frac{x(x^2 + 1)}{(x + 1)}]

3/2 is before ln. so we move the fraction 3/2 to the exponent

as per log property we move the fraction to the exponent

[ln \frac{x(x^2 + 1)}{(x + 1)}]^\frac{3}{2}

6 0
3 years ago
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