Question

Which is the equation of the line that passes through (6, 2) and is perpendicular to a line with slope -1/3?

Answer 1

Answer:

$\boxed{\text{C. } y - 2 = 3(x - 6)}$

Step-by-step explanation:

The slope of the perpendicular line m₂ must  be the negative reciprocal of the slope m₁ of the first line.

$m_{2} = -\dfrac{1}{m_{1}} = -\dfrac{1}{-\frac{1}{3}} = 3$

The only equation with m = 3 is  

$\boxed{\textbf{C. } y - 2 = 3(x - 6)}$

This is the point slope form of the equation for a straight line through (6, 2) with slope = 3.

Answer 2

Answer:

C

Step-by-step explanation:

$\frac{ - 1}{3} \times a = -1$

then

$a = 3 \: where \: a \: is \: our \: line \: slope$