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ANTONII [103]
3 years ago
10

Whic two transformations are applied to pentagon ABCDE to create A'B'C'D'E?

Mathematics
2 answers:
Blababa [14]3 years ago
8 0
It's either a (the first one) or b (the second one), but if I had to choose I would choose b. If I'm wrong I'm so sorry I spent 10 minutes looking at this.
TEA [102]3 years ago
5 0

Answer:

Option A.

Step-by-step explanation:

ABCDE is a pentagon which has been transformed to form A'B'C'D'E'.

In this process two transformations have been done.

To check the transformations we select one point A and check it for all the transformations.

1) Point A has been shifted 7 units right on the x axis and 1 unit up on y- axis as per rule (x, y) → (x + 7, y + 1)

2) Now the translated image has been reflected across x - axis to form a new point A'.

Therefore, Option A. is the correct option.

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Which number line shows the solution of 5x-25&lt;-15?<br> givning brainliest
Nata [24]

Answer:

x < 2

Step-by-step explanation:

5x-25<-15

Add 25 to each side

5x-25+25<-15+25

5x < 10

Divide by 5

5x/5 < 10/5

x < 2

Open circle at 2   line to left

6 0
1 year ago
Goods bought for $800 had to be sold off at a loss of 8% the selling price was​
Vikentia [17]

Answer:

8% of 800 is 64

800-64=736

Step-by-step explanation:

4 0
2 years ago
One of Tyler’s chores is to feed the chickens. Two bags of chicken feed will last 5 days. How many days will 8 bags of chicken f
aleksley [76]

Answer:

20days

Step-by-step explanation:

1 bag feed : 5/2 = 2.5 days

8 bags feed : 2.5*8 = 20 days

5 0
3 years ago
Write a rule to describe the function shown. x y −6 −4 −3 −2 0 0 3 2 y equals start fraction two over three end fraction x y equ
sertanlavr [38]

Answer:

y=\frac{2}{3} x (y equals start fraction two over three end fraction x)

Step-by-step explanation:

Lest's organize the table values of our function first:

x    y

-6  -4

-3  -2

0   0

3   2

The simplest kind of of function is a linear function of the form y=mx+b where m is the slope and b is the y-intercept. Let's us check if our function is a linear one finding its equation and checking that all points are in the line.

The first step to find a linear equation is find the slope of the line; to do it, we are using the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

where

m is the slope of the line

(x_1,y_1) are the coordinates of the first point

(x_2,y_2) are the coordinates of the second point

We know from our table that the first and second points are (-6, -4) and (-3, -2) respectively, so x_1=-6, y_1=-4, x_2=-3, and y_2=-2.

Replacing values:

m=\frac{y_2-y_1}{x_2-x_1}

m=\frac{-2-(-4)}{-3-(-6)}

m=\frac{-2+4}{-3+6)}

m=\frac{2}{3)}

Now that we have the slope of our line we can use the point slope formula to complete our linear function:

y-y_1=m(x-x_1)

where

m is the slope

(x_1,y_1) are the coordinates of the first point

Replacing values:

y-y_1=m(x-x_1)

y-(-4)=\frac{2}{3)}(x-(-6))

y+4=\frac{2}{3)}(x+6)

y+4=\frac{2}{3} x+4

y=\frac{2}{3} x+4-4

y=\frac{2}{3} x

Now, to check if our function is valid, we can either check if each point satisfies the rule y=\frac{2}{3} x, or we can graph it and check if each lies is in the graph.

Let's check both:

We already know that points (-6, -4) and (-3, -2) satisfy the rule (after all, those were the point we used to came out with the rule in the first place), so we just need to check the points (0, 0) and (3, 2)

- For (0, 0):

y=\frac{2}{3} x

0=\frac{2}{3}(0)

0=0

The point satisfies the rule.

- For (3, 2):

y=\frac{2}{3} x

2=\frac{2}{3} (3)

2=2

The point satisfies the rule.

Since all the points of our table satisfies the rule y=\frac{2}{3} x, we can conclude that the rule describing the function shown is y=\frac{2}{3} x.

4 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
GrogVix [38]

Answer:

  1. D. f^-1(x) = log2(x -6)
  2. 4x^2 -3 . . . . x ≤ 0
  3. B. √(x^5) -3√(x^3) -18√x

Step-by-step explanation:

1. When you replace f(x) by x and x by y, you have

... x = 2^y + 6

The first thing you do is subtract 6; then you take the base-2 logarithm:

... (x -6) = 2^y

... log2(x -6) = y = f^-1(x)

You know that to get the y-term by itself, you must subtract 6. Anything else you do will operate on (x-6). Only answer choice D has that sort of construction.

2. When you swap x and y and solve for y, you have ...

... x = -1/2√(y+3)

... -2x = √(y +3) . . . . . . multiply by -2

... (-2x)^2 = y +3 . . . . . square

... 4x^2 - 3 = y = f^-1(x) . . . . subtract 3

The range of f(x) is (-∞, 0], so that is the domain of f^-1(x). That is, f^-1(x) is defined for x ≤ 0.

3. The product of the two functions is ...

... (x -6)(√x)(x +3) = (√x)(x^2 -3x -18)

<em>Every term</em> will have a factor of √x, and the coefficients will be 1, -3, -18. Only selection B matches those conditions.

7 0
2 years ago
Read 2 more answers
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