1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luden [163]
3 years ago
7

Type your response in the box.

Chemistry
1 answer:
nata0808 [166]3 years ago
7 0
I believe deforestation increases the biodiversity of a forest ecosystem. Trees are an essential organism for all ecosystem and forms of life. Without trees we have no oxygen, however trees so reproduce, but when you are chopping them down at the rate of deforestation(hence how it got it's name) then there is an issue
You might be interested in
5. List four examples of neutralization reactions and four for acid-base reactions. You can revisit last week's lesson #
garik1379 [7]

Answer:

Reacciones de neutralización

Mg(OH)2

NaHCO3

Bicarbonato de sodio

Cloruro de sodio

Reacciones acido base

HCl + NaOH → NaCl + H2O.

H2SO4 + 2 NaOH → Na2SO4 + H2O.

HCl + NH3 → NH4Cl + H2O.

HCN + NaOH → NaCN + H2O.

Explanation:

7 0
3 years ago
A chemical reaction in which two or more elements switch places is called?
Nina [5.8K]

Answer:

neutralization

Explanation:

8 0
3 years ago
What is the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml?
Firdavs [7]

Answer: The final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,  

M_1 = molarity of stock CuSO_4 solution = 2.5 M

V_1 = volume of stock CuSO_4solution = 5 ml  

M_1 = molarity of diluted CuSO_4 solution = ?

V_1 = volume of diluted CuSO_4 solution = 750 ml

Putting in the values we get:

2.5\times 5=M_2\times 750

M_2=0.017

Therefore the final concentration when 5 ml of a 2.5M copper sulphate solution is diluted to 750 ml is 0.017 M

6 0
3 years ago
Large objects that form dense gravity wells in space A. Galaxies B. Star C. Nebulae D. Black holes.​
BigorU [14]

Answer:

D. Black Holes

Explanation:

Black holes are large objects that form dense gravity wells in space. Their gravitational pull is so strong that even light cannot escape it. 

5 0
3 years ago
Read 2 more answers
A student used 1.168g of an unknown weak acid and titrated it against 28.75 mL of 0.105M NaOH to reach the equivalence point. Wh
Vaselesa [24]

Answer:

The molar mass of the unknown acid is 386.8 g/mol

Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

Molarity of NaOH = 0.105 M

Since we only know 1 equivalence point, we suppose the acid is monoprotic

Step 2: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.105 M * 0.02875 L

Moles NaOH = 0.00302 moles

We need 0.00302 moles of weak acid to neutralize the NaOH

Step 3: Calculate molar mass of weak acid

Molar mass = mass / moles

Molar mass = 1.168 grams / 0.00302 moles

Molar mass = 386.8 g/mol

The molar mass of the unknown acid is 386.8 g/mol

3 0
3 years ago
Other questions:
  • What is the rise and fall of ocean water are called
    10·2 answers
  • A 250. ML sample of 0.3M HCl is partially neutralized by the addition of 100. ML of 0.25M NaOH.Find the concentration of hydroch
    7·1 answer
  • Consider the following chemical equation in equilibrium.
    9·2 answers
  • How much does 200 gallons of water weigh?
    9·1 answer
  • In details explain element
    9·2 answers
  • Which changes can reach dynamic equilibrium
    14·1 answer
  • Sunlight Grass → Rabbit + Snake
    8·2 answers
  • JOIN MY AMONG US GAME TELL ME IF YOU JOIN THE CODE IS QUVNDF PLEASE JOIN
    13·2 answers
  • Describe how the periodic
    9·1 answer
  • What is the mass in grams of 3.40 x 10 24 atoms he
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!