Question

To three significant digit,what is the mass percentage of iron in the compound Fe2O3​

Answer 1

69.9%

Explanation:

To find the mass percentage of iron in the compound in Fe₂O₃, we would go ahead to express the given molar mass of the iron to that of the compound.

 Mass percentage  = $\frac{molar mass of Fe}{Molar mass of Fe_{2}O_{3} }$  x 100

Molar mass of Fe = 55.85g/mol

Molar mass of O = 16g/mol

Molar mass of Fe₂O₃ = 2(55.85) + 3(16) = 159.7‬g/mol

Mass percentage  = $\frac{2(55.85)}{159.7} x 100$   = 69.94% = 69.9%

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Mass percentage brainly.com/question/8170905

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