Answer:
126000J
Explanation:
From the question given, we obtained the following information:
M = 1500g
C = 4.2J/g°C
ΔT = 20°C
Q =?
Q= MCΔT
Q = 1500 x 4.2 x 20 =
Q = 126000J
Answer:
1.6g/mL
Explanation:
Density equation is D=m/v
Density = g/mL
m=mass of sample in grams
v = volume of sample in mL
The volume of a square can be calculated by V=l*w*h.
In this case it is 5cm*5cm*5cm = 125cm^3
Since we know that 1cm^3 ~ 1mL we can convert the volume to mL as so:
125cm^3 (1mL/(1cm^3)) = 125mL
Then simply plug into the density equation:
D=200g/125mL = 1.6g/mL
So they can tell what exact species it is.
Answer:
The final temperature is:- 7428571463.57 °C
Explanation:
The expression for the calculation of heat is shown below as:-
Where,
is the heat absorbed/released
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of water = 1.75 mg = 0.00175 g ( 1 g = 0.001 mg)
Specific heat of water = 4.18 J/g°C
Initial temperature = 35 °C
Final temperature = x °C
![\Delta T=(x-35)\ ^0C/tex] Q = [tex]1.3\times 10^4](https://tex.z-dn.net/?f=%5CDelta%20T%3D%28x-35%29%5C%20%5E0C%2Ftex%5D%0A%3C%2Fp%3E%3Cp%3EQ%20%3D%20%5Btex%5D1.3%5Ctimes%2010%5E4)
kcal
Also, 1 kcal = 4.18 kJ = 
J
So, Q = 
J = 54340000 J
So,
Thus, the final temperature is:- 7428571463.57 °C
HNO3+NaOH ----> H2O
H⁺ +NO3⁻+Na⁺+OH⁻ ---> Na⁺ +NO3⁻ +H2O
H⁺ (aq)+OH⁻(aq)----> H2O(l)
