Answer:
No, there is no evidence that the manufacturer has a problem with underfilled or overfilled bottles, due that according our results we cannot reject the null hypothesis.
Explanation:
according to this exercise we have the following:
σ^2 =< 0.01 (null hypothesis)
σ^2 > 0.01 (alternative hypothesis)
To solve we can use the chi-square statistical test. To reject or not the hypothesis, we have that the rejection region X^2 > 30.14
Thus:
X^2 = ((n-1) * s^2)/σ^2 = ((20-1)*0.0153)/0.01 = 29.1
Since 29.1 < 30.14, we cannot reject the null hypothesis.
Answer:
22.8 L
Explanation:
Step 1: Given data
- Moles of the gas (n): 1.35 mol
- Pressure of the gas (P): 1.30 atm
- Ideal gas constant (R): 0.0821 atm.L/mol.K
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15 = -6 + 273.15 = 267 K
Step 3: Calculate the volume of the gas
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 1.35 mol × (0.0821 atm.L/mol.K) × 267 K / 1.30 atm
V = 22.8 L
Answer:
I should use a volumetric flask.
Explanation:
If the accuracy of the concentration is important, we need to use a volumetric flask.
Answer:
3) O(g) is an intermediate; 2O3(g)→3O2(g)
Explanation:
The decomposition of ozone to yield oxygen occurs in a sequence of steps. The various non-elementary reactions involved constitute the reaction mechanism. In the sequence of reaction steps O(g) serves as an intermediate.
The overall reaction involves the conversion of two moles of ozone to three moles of oxygen as shown in the answer. Thus the O(g) is merely a reaction intermediate.