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1 year ago

PLEASE HELP DUE TONIGHT THANK YOU

Chemistry

1 answer:

Sav [38]1 year ago

3 0

Answer:

check the attached image. hope it helps

Explanation:

a. What does mol/L mean? mol/L means Molar Concentration

b. Describe in your own words how mol/L compares to grams/liter. (similarities and differences)

Similarities: mol/L and grams/liter both are units of concentration.

Differences:

mol/L concentration says how many moles of solute are present in 1L of solution.

grams/liter concentration says how many grams of solute are present in 1L of solution.

3. Describe at least 2 ways in the simulation to change each of the parameters:

a. Volume of solution= evaporating or adding more water

b. amount of solute=reducing the water or evaporating more water

c. Concentration of solute in solution = evaporating or adding more solute

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AleksAgata [21]

I think the answer would be trenches but I’m sorry if I’m wrong

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2 years ago

Which of these half-reactions represents reduction?

gogolik [260]

Answer: The half-reactions represents reduction are as follows.

$Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}$
$MnO^{-}_{4} \rightarrow Mn^{2+}$

Explanation:

A half-reaction where addition of electrons take place or a reaction where decrease in oxidation state of an element takes place is called reduction-half reaction.

For example, the oxidation state of Cr in $Cr_{2}O^{2-}_{7}$ is +6 which is getting converted into +3, that is, decrease in oxidation state is taking place as follows.

$Cr_{2}O^{2-}_{7} + 3 e^{-} \rightarrow Cr^{3+}$

Similarly, oxidation state of Mn in $MnO^{-}_{4}$ is +7 which is getting converted into +2, that is, decrease in oxidation state is taking place as follows.

$MnO^{2-}_{4} + 5 e^{-} \rightarrow Mn^{2+}$

Thus, we can conclude that half-reactions represents reduction are as follows.

$Cr_{2}O^{2-}_{7} \rightarrow Cr^{3+}$
$MnO^{-}_{4} \rightarrow Mn^{2+}$

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2 years ago

Hydrogen iodide is not produced by the same method is for hydrogen chloride why with reaction

Masja [62]

Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...

Using an ionic chloride and Phosphoric acid

H3PO4 + NaCl ==> HCl + NaH2PO4

H3PO4 + NaI ==> HI + NaH2PO4

H2SO4 + NaCl ==> HCl + NaHSO4

This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.

The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.

2I-² === I2 + 2e-

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2 years ago

What are some natural resources that are limited on earth

inysia [295]

Answer:

oil, ores, and fossils.

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2 years ago

Describe an experiment to show that water contains hydrogen and oxygen only

kondaur [170]

Answer:

Electrolysis

Explanation:

The electrolysis of water is one such experiment that shows that water is made up of hydrogen and oxygen atoms only in the ratio of 2 to 1.

In the electrolysis of water, electricity is passed through acidified water to cause it to decompose.

The electrolysis of water is also known as the electrolysis of dilute tetraoxosulphate (VI) acid.

At the cathode, H⁺ ions are discharged and hydrogen gas is liberated:

2H⁺ + 2e⁻ → H₂

At the anode, both the sulfate ion and hydroxyl ions migrate to this electrode. Only the OH⁻ is selected for preferential discharge due to its lower position in that activity series.

4OH⁻ → 2H₂O + O₂ + 4e⁻

Oxygen gas is produced at the anode.

This electrolysis demonstrates the volumetric composition of water that is, 2 volumes of hydrogen at the cathode and 1 volume of oxygen at the anode.

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2 years ago