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kirza4 [7]
2 years ago
7

HELP ME PLEASE!!!! I NEEDZ HELP!!!

Chemistry
1 answer:
Anuta_ua [19.1K]2 years ago
3 0
It goes Meter mega meter giga meter and kilometer
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So no one go help me wit my chemistry huh
kramer

Answer:

depends...

on how difficult it is

5 0
3 years ago
Read 2 more answers
Classify each of the following reactions as either exothermic or endothermic: 2H,O(l) + heat → 2H₂(g) + O₂(g)​
Murljashka [212]

Answer:

endothermic

Explanation:

It is endothermic since it absorbs heat.  If the reaction RELEASED heat (exothermic) the "+ heat" would be on the right side of the equation.

6 0
1 year ago
According to which theory or law is a chemical reaction most likely to occur when two particles with the proper energy and orien
Nat2105 [25]
<h2>Collision Theory </h2>

Explanation:

<h3>The given statement is related to the collision theory - </h3>

Collision theory was given by William Lewis in 1916.

This theory explains in a qualitative manner that in what way any chemical reaction occurs and the reason for the different reaction rates for different reactions.

<h3>According to the collision theory - </h3>
  • Molecules must collide in order to react
  • Sufficient amount of energy is needed for collisions (kinetic energy) so that the chemical bonds should break
  • This energy used is known as the activation energy
  • On the increase in the temperature, the kinetic energy of the molecule increases and the molecules move faster and collide with a proper orientation at an increased speed
  • This increases the rate of a collision that in turn increases the breaking of the bond  

6 0
2 years ago
3 mol of nitrogen gas reacts with 6 mol of hydrogen gas. how many mol of gaseous product is produced
jenyasd209 [6]
Your answer would 6 Moles
6 0
3 years ago
A mixture of 15.0 g of the anesthetic halothane (C2HBrClF3 197.4 g/mol) and 22.6 g of oxygen gas has a total pressure of 862 tor
AlexFokin [52]

Answer : The partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

Explanation : Given,

Mass of C_2HBrClF_3 = 15.0 g

Mass of O_2 = 22.6 g

Molar mass of C_2HBrClF_3 = 197.4 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_2HBrClF_3 and O_2.

\text{Moles of }C_2HBrClF_3=\frac{\text{Mass of }C_2HBrClF_3}{\text{Molar mass of }C_2HBrClF_3}=\frac{15.0g}{197.4g/mole}=0.0759mole

and,

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{22.6g}{32g/mole}=0.706mole

Now we have to calculate the mole fraction of C_2HBrClF_3 and O_2.

\text{Mole fraction of }C_2HBrClF_3=\frac{\text{Moles of }C_2HBrClF_3}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.0759}{0.0759+0.706}=0.0971

and,

\text{Mole fraction of }O_2=\frac{\text{Moles of }O_2}{\text{Moles of }C_2HBrClF_3+\text{Moles of }O_2}=\frac{0.706}{0.0759+0.706}=0.903

Now we have to partial pressure of C_2HBrClF_3 and O_2.

According to the Raoult's law,

p^o=X\times p_T

where,

p^o = partial pressure of gas

p_T = total pressure of gas

X = mole fraction of gas

p_{C_2HBrClF_3}=X_{C_2HBrClF_3}\times p_T

p_{C_2HBrClF_3}=0.0971\times 862torr=84torr

and,

p_{O_2}=X_{O_2}\times p_T

p_{O_2}=0.903\times 862torr=778torr

Therefore, the partial pressure of C_2HBrClF_3 and O_2 are, 84 torr and 778 torr respectively.

6 0
2 years ago
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