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Travka [436]
3 years ago
6

The reaction for photosynthesis producing glucose sugar and oxygen gas is:

Chemistry
1 answer:
Anvisha [2.4K]3 years ago
5 0

<u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

So, in this case, the balanced reaction is:

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:

  • CO₂: 6 moles
  • H₂O: 6 moles
  • C₆H₁₂O₆: 1 mole
  • O₂: 6 moles

So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:

moles of CO_{2} =2.20 grams*\frac{1 mole}{44.01 grams}

moles of CO₂= 0.05 moles

Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?

moles of C_{6} H_{12} O_{6} =\frac{0.05moles of CO_{2} *1 mole of C_{6} H_{12} O_{6}}{6moles of CO_{2}}

moles of C₆H₁₂O₆= 8.33*10⁻³

Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:

mass of glucose =8.33*10^{-3} moles*\frac{180.18 grams}{1 mole}

<em>mass of glucose= 1.5 grams</em>

Then, <u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

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Calcium hydroxide, Ca(OH)2, is an ionic compound with a solubility product constant, Ksp, of 6.5×10–6. Calculate the solubility
kari74 [83]

Answer: The solubility of this compound in pure water is 0.012 M

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}

The equation for the ionization of the  is given as:

Ca(OH)_2\rightarrow Ca^{2+}+2OH^-  

By stoichiometry of the reaction:

1 mole of  Ca(OH)_2 gives 1 mole of Ca^{2+} and 2 mole of OH^-

When the solubility of  Ca(OH)_2 is S moles/liter, then the solubility of Ca^{2+}  will be S moles\liter and solubility of OH^- will be 2S moles/liter.

K_{sp}=[Ca^{2+}][OH^{-}]^2

6.5\times 10^{-6}=[S][2S]^2

S=0.012M

Thus solubility of this compound in pure water is 0.012 M

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What are the three (3) things involved in stoichiometry problems???
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