Question

The temperature of a sample of gas in a steel tank at 0.30 ATM at 25 Celsius if the pressure W20.59 ATM what would be the final temperature inside the tank in kelvin

Answer 1

The final temperature : 313.06 °C

Further explanation

Gay Lussac's Law  

When the volume is not changed, the gas pressure is proportional to its absolute temperature  

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

P1=0.3 atm

T1=25 + 273=298 K

P2=0.59 atm

$\tt \dfrac{0.3}{298}=\dfrac{0.59}{T_2}\\\\T_2=586.06=313.06~^oC$