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german
3 years ago
12

Geetha took some grains of boiled rice in test tube A and Tina took boiled and chewed rice in test tube B. Both of then poured 1

-2 drops of iodine solution into the test tubes. What would they have observed? Give a reason for your answer.
Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
6 0

Answer:

Test tubes A and B turn a darker blue color.

Explanation:

Based on the information provided in the question it can be said that they should have noticed that Tube A and Tube B turned a dark blue color. This is because the starch turns the solution in the test tubes into a dark blue color due to the negative reaction caused by the conversion of starch present in salivary amylase

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What is the molarity of a solution in which 0.321 g of calcium chloride is dissolved in 1.45 L water?
lana66690 [7]

Answer:

Molarity = 0.002 M

Explanation:

Given data:

Mass of calcium chloride = 0.321 g

Volume of water = 1.45 L

Molarity of solution = ?

Solution:

Molarity = number of moles / volume in litter.

We will calculate the number of moles of calcium chloride first.

Number of moles = mass/molar mass

Number of moles = 0.321 g/ 110.98 g/mol

Number of moles = 0.003 mol

Molarity:

Molarity = 0.003 mol / 1.45 L

Molarity = 0.002 M

7 0
3 years ago
if 1.386 g of mg ribbon combusts to form 2.309 g of oxide product, calculate the experimental mass percent of oxygen from this d
Pavlova-9 [17]

1.386 g of Mg ribbon combusts to form 2.309 g of oxide product. The mass percent of oxygen in the oxide is 40.0 %.

Let's consider the reaction for the combustion of Mg.

Mg + 1/2 O₂ ⇒ MgO

1.386 g of Mg combusts to form 2.309 g of MgO. We want to determine the mass of oxygen in MgO. According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Then, the mass of Mg in the reactants is equal to the mass of Mg in MgO. The mass of the magnesium oxide is the sum of the masses of magnesium and oxygen. The <u>mass of oxygen in the oxide</u> is:

mMgO = mMg + mO\\mO = mMgO - mMg = 2.309 g - 1.386 g = 0.923 g

We can calculate the mass percent of O in MgO using the following expression.

\% O = \frac{mO}{mMgO} \times 100\% = \frac{0.923 g}{2.309g} \times 100\%  = 40.0 \%

You can learn more about mass percent here: brainly.com/question/14990953

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The horse achieved its highest status during the___________dynasty (618-906 CE), a time of unparalleled political, artist, and c
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What part of an atom orbits around the center of the atom?
Zanzabum

Answer:

electrons.

Explanation:

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