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3 years ago

9

2. Question: How much water is best for a pea plant to grow?

1 answer:

snow_lady [41]3 years ago

4 0

Answer:

Explanation:

Growing Peas

Planting depth should be roughly 2 inches with a spacing of about 2 inches apart. Water well at planting and provide at least 1 inch of water per week, particularly during the flowering and pod production stages. As the temperature rises, the vines may need to be deeply watered almost every day.

Make sure to moniter it and change the water depending on how dry or overwatered it looks like. :)

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Describe the factors which make an organism living

Anvisha [2.4K]

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3 years ago

- How much power does it take to lift a<br> 1,000 N load 10 m in 20 s?

Mariana [72]

Answer:

"500 Joule/sec" is the right answer.

Explanation:

The given values are:

Force,

F = 1000 N

Velocity,

s = 10 m

Time,

t = 20 s

Now,

The power will be:

= $\frac{Force\times Velocity}{Time}$

On putting the values, we get

= $\frac{1000\times 10}{20}$

= $\frac{10000}{20}$

= $500 \ Joule/sec$

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3 years ago

How many particles are in 13.5 grams of Beryllium ?

Marina86 [1]

Explanation:

I don't know this answer what Hydrogen Helium lithium

4 0

2 years ago

Read 2 more answers

1. If I have 3 identical books that all have a length of 25cm, a

Ksenya-84 [330]

Answer:

12,375 cm³

Explanation:

v=l×w×h

Since there are 3 books the equation would then be

v=3(l×w×h)

v=3(25×15×11)

v=3(4,125)

v=12,375 cm³

5 0

3 years ago

ubstance A undergoes a first order reaction A®B with a half-life, t½, of 20 min at 25 °C. If the initial concentration of A in a

Stells [14]

Answer : The concentration of A after 80 min is, 0.100 M

Explanation :

Half-life = 20 min

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{20\text{ min}}$

$k=3.465\times 10^{-2}\text{ min}^{-1}$

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $3.465\times 10^{-2}\text{ min}^{-1}$

t = time passed by the sample = 80 min

a = initial amount of the reactant = 1.6 M

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$80=\frac{2.303}{3.465\times 10^{-2}}\log\frac{1.6}{a-x}$

$a-x=0.100M$

Therefore, the concentration of A after 80 min is, 0.100 M

3 0

2 years ago