Answer:
Hydrometers
Density can be measured using a variety of instruments. A hydrometer is used to determine the density
Explanation:
Matter and substance are definitely related. All substances
are matter but all matters are not substance. A matter can consist of numerous
substances. Matter is generally a loose term used in respect to a substance.
Any physical object can be casually called a matter. Matter and substance are
sometimes used for the same context, but it is completely wrong. Numerous
examples have already proved that a matter may or may not be a substance
depending on its physical nature, but a substance is always a matter.
Answer:
91.5 mol
Explanation:
Volume of gas = 70 L
Temperature = 25°C
Pressure = 32 atm
Moles of gas = ?
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
Now we will convert the temperature.
25+273.15 = 298.15 K
By putting values,
32 atm × 70 L = n ×0.0821 atm.L /mol.K × 298.15 K
2240 atm.L = n ×24.48 atm.L /mol
n = 2240 atm.L / 24.48 atm.L /mol
n = 91.5 mol
Data:
<span>Solute: 28.5 g of glycerin (C3H8O3)
Solvent: 135 g of water at 343 k.
Vapor pressure of water at 343 k: 233.7 torr.
Quesiton: Vapor pressure of water
Solution:
Raoult's Law: </span><span><span>The vapour
pressure of a solution of a non-volatile solute is equal to the vapour
pressure of the pure solvent at that temperature multiplied by its mole
fraction.
Formula: p = Xsolvent * P pure solvent
X solvent = moles solvent / moles of solution
molar mass of H2O = 2*1.0g/mol + 16.0 g/mol = 18.0 g/mol
moles of solvent = 135 g of water / 18.0 g/mol = 7.50 mol
molar mass of C3H8O3 = 3*12.0 g/mol + 8*1 g/mol + 3*16g/mol = 92 g/mol
moles of solute = 28.5 g / 92.0 g/mol = 0.310 mol
moles of solution = moles of solute + moles of solvent = 7.50mol + 0.310mol = 7.810 mol
Xsolvent = 7.50mol / 7.81mol = 0.960
p = 233.7 torr * 0.960 = 224.4 torr
Answer: 224.4 torr
</span> </span>
A) 10.0g of Iron is
of Iron.
One mole of dihydrogen is required to form one mole of iron, hence you'll need
of dihydrogen.
B) Likewise : 2.50g of Iron is
of Iron, hence we'll need
of Fe2O3.
