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Firlakuza [10]
3 years ago
10

The specific heat of aluminum is 0.900 J/gº C. A 400.0 g sample of aluminum at 20.0º C absorbs 2520. J of heat energy. What is t

he new temperature of the aluminum?
Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
8 0
I'm pretty sure it's 8 xd
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Atoms are the building blocks of all matter
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3 years ago
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What does osmosis depend on? A. the identity of the solute and solvent B. how much solvent is present in the solution C. the num
KengaRu [80]

Osmosis is a special kind of diffusion where solvent particles move through a semi permeable membrane from low concentration of solute to high concentration of solute.

so it depends upon

a) how much solvent is present : More the solvent on one side of semipermeable membrane more the movement of solvent particles on the other side of membrane


6 0
3 years ago
What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?
Ymorist [56]

Answer:

\% diss = 50\%

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}

Thus, it is possible to find x given the pH as shown below:

x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M

So that we can calculate the initial concentration of the acid:

\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\

[HA]_0=3.64x10^{-5}M

Therefore, the percent dissociation turns out to be:

\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%

Best regards!

6 0
3 years ago
What units are used to measure energy? A) volts B) angstroms C) centimeters D) joules
Usimov [2.4K]

Answer:

joules

Explanation:

it is the measurement of energy

7 0
3 years ago
Hno3, a strong acid, is added to shift the ag2co3 equilibrium (equation 7.6) to the right. explain why the shift occurs.
Deffense [45]
Answer 1)  When a strong acid like HNO_{3} reacts with Ag_{2} CO_{3} usually the equilibrium shifts to the right because

As per the Le chatelier's principle "if in any reaction, a dynamic equilibrium is disturbed by changing the any of the conditions, the position of equilibrium moves to counteract the change."  So, in the given reaction when HNO_{3} reacts with Ag_{2} CO_{3}  it generates carbon dioxide and water as a by product, if we are adding HNO_{3} it will remove some of the CO_{3} molecule from the reaction mixture, which then tends to shift the equilibrium towards right.

Answer 2) The same would be observed in this case, if we replace HNO_{3} with HCl it will shift the equilibrium to the right as their will be generation of AgCl as the precipitate.

As per the definition of Le Chatelier's principle if we add reactants in the reaction the equilibrium will tend to move towards right, also if we replace the products or remove it then too it will shift the equilibrium towards right. So, in this reaction you are removing Ag^{+} and Cl^{-} ions from the solution.
7 0
3 years ago
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